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marysya [2.9K]
2 years ago
11

What is 35% of 60? just had to be 20 words

Mathematics
2 answers:
Vladimir [108]2 years ago
4 0

Answer:

35% of 60 = 21

Anika [276]2 years ago
3 0

the answer is 21

this is how you set it up

x/60=35/100

you first multiply 35 and 60 and your answer should be 2100 then you divide 2100 by 100 and that equals 21

i hope this helped i learned about this a month ago

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An expression to convert 50 miles per hours to miles per minute is shown
MariettaO [177]
Hello

The correct number would be 0.8333

Have a nice day
7 0
2 years ago
Read 2 more answers
What is the rate of change ?
postnew [5]
The rate of change is also called the slope
 the formula foe the rate of change is (y2-y1) / (x2-x1)

x1 = -3
x2 = 6
y1 = 14
y2 = -1
 rate of change = (-1 - 14) / (6- (-3)
= -15 / 9
= -5/3


3 0
3 years ago
1 -12.166 + (-1.54)​
castortr0y [4]

Answer:

-12.706

Step-by-step explanation:

First we distribute: 1 - 12.166 - 1.54

Then we subtract: -12.706

8 0
3 years ago
Mrs. Greensmith works a PC Richards and earns $35 per week plus a 12% commission o sales. How much would she earn for the week i
n200080 [17]
Answer: $245

she makes $35 every week (her wage, i’m assuming) regardless of how many sales she makes.

in order to find out how much money she makes out of her sales, you have to multiply the percentage commission by how much her sales was: so .12x1750 = $210 from sales.

you then add up her wage and her sales money, so $35 from wage + $210 from sales = $245 total for the week

answer: $245
8 0
2 years ago
Read 2 more answers
There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f
Ann [662]

Answer:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated population proportion for this case is:

\hat p = \frac{350}{500}=0.7

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0
2 years ago
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