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kvv77 [185]
3 years ago
5

What is the surface area of this right rectangular prism with dimensions of 4 centimeters by 4 centimeters by 6 centimeters?

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
A = 2(WL + HL + HW)
A = 2(4*4 + 6*4 + 6*4)A = 2(16 +24 +24)
A =2(64)
A=128CM

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Renee is creating a rectangular garden in her backyard. The length of the garden is 8 feet. The perimeter of the garden must be
WARRIOR [948]

Answer: One width of the garden can be 3.8 feet.

Step-by-step explanation: To find the perimeter of the garden, multiply the length by the width. Our width is 3.8 feet and our length is 8 feet.

3.8 x 8 = 30.4 feet.

The perimeter could be 30.4 feet because the garden is at least 30 feet and no more than 32 feet.

So, a width of 3.8 feet would work.

7 0
3 years ago
A baseball team plays in a stadium that holds 62000 spectators. With the ticket price at $11, the average attendance has been 27
sasho [114]

Answer:

$15.625

Step-by-step explanation:

Let the revenue collected be R and price per spectator be p then the number of spectators be N. Therefore

R=Np

Using equation of slope of y=mx +c where m is gradient and c is y-intercept

When p=$11, N=27000 and when p=$8, N=31000

The gradient, m will be

m=\frac {31000-27000}{8-11}= -1333.33

To get the y-intercept

N=-1333.33p+c

When spectator number n is 27000, the price p is $11

27000=-1333.33(11)+c hence we solve c

c=27000+(11*1333.33)= 41666.67

Therefore, the linear equation is

N=-1333.33p+ 41666.67

Substituting the linear equation into R=Np we obtain

R=p(-1333.33p+41666.67)

R=-1333.33p^{2}+41666.67p

To obtain maximum revenue, we differentiate the above with respect to price hence obtain

0=2*-1333.33p+41666.67

p=-\frac {41666.67}{2(-1333.33)}= 15.625

Therefore, the price that maximizes revenue is $15.625

4 0
3 years ago
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Ann [662]

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Step-by-step explanation:

solved with delta way

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2 years ago
8(5b + 3) = 10(4b + 2)
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Answer:

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Step-by-step explanation:

4 0
3 years ago
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adell [148]

Answer:

Step-by-step explanation:

tany+coty =

\frac{siny}{cosy} + \frac{cosy}{siny}·

\frac{sin^{2}y + cos^{2}y  }{cosysiny}

\frac{1}{cosysiny}

(secy) (cscy)

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3 years ago
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