Answer : The equilibrium concentration of
is, 0.50 M
Explanation : Given,
Initial moles of
= 0.65 mole
Volume of solution = 1.0 L
Moles of
at equilibrium = 0.15 mole
The balanced equilibrium reaction will be,

Initial moles 0.65 0 0
At eqm. (0.65-x) x x
Moles of
at equilibrium = x = 0.15 mole
Moles of
at equilibrium = x = 0.15 mole
Moles of
at equilibrium = (0.65-x) = (0.65-0.15) = 0.50 mole
Now we have to calculate the concentration of
at equilibrium.
Formula used : 



Therefore, the equilibrium concentration of
is, 0.50 M
I think it’s B energy of the reactants
A battery transforms two types of energy, chemical energy to electrical energy.
Answer: Chemical and electrical energy
Answer:
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
Explanation:
![Rate = k[AB]^2](https://tex.z-dn.net/?f=Rate%20%3D%20k%5BAB%5D%5E2)
The order of the reaction is 2.
Integrated rate law for second order kinetic is:
Where,
is the initial concentration = 1.50 mol/L
is the final concentration = 1/3 of initial concentration =
= 0.5 mol/L
Rate constant, k = 0.2 L/mol*s
Applying in the above equation as:-


<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>