Answer:
Methyl pentanoate.
Explanation:
Hello there!
In this case, according to the given information, we can see the correct structure will be:
O
||
CH3CH2CH2CH2COCH3
Which matches with the structure of an ester due to the -COO- functional group. In such a case, the first part of the name is in function of the right side of the ester, in this case, methyl, followed by the left side, pentanoate, as it has five carbon atoms and is an ester (similar to an inorganic salt, but organic) and therefore, the name will be methyl pentanoate.
Regards!
570/8.5=67.0 58... you only have to take the natural part, si the answer is 67 students
AgNO₃ will act as the oxidising agent.
<h3><u>For the given chemical equation:</u></h3>
Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂
Half reactions for the given chemical reaction:
<u>Reducing agent:</u>
Cu → Cu²⁺ + 2e⁻
Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.
<u>Oxidising Agent</u>:
Ag⁺ + e⁻ → Ag
The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.
Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.
<h3><u>
Oxidising and Reducing agents</u></h3>
- An oxidizing agent is a substance that reduces itself after oxidizing another material. It passes through a reduction process in which it obtains electrons and the substance's oxidation state is decreased.
- A reducing agent is a chemical that oxidizes after reducing another material. It passes through an oxidation process in which it loses electrons and the substance's oxidation state increases.
To know more about the process of Oxidation and Reduction, refer to:
brainly.com/question/4222605
#SPJ4
Answer is: -963,8 kJ.
Q₁ = m(Fe) · C · ΔT₁.
C - specific heat capacity of liquid iron, C(Fe) = 0,82 J/g°<span>C.
</span>m(Fe) = 575 g.
ΔT₁ = 1181 - 1825 = -644°C.
Q₁ = -859306,5 J = -859,3 kJ.
Q₂ = m(Fe) · C · ΔT₂.
ΔT₂ = 293 - 1181 = -888°C.
C - specific heat capacity, C(Fe) = 0,44 J/g°C.
Q₂ = -224664 J = -224,66 kJ.
Q₃ =- heat of fusion, ΔH = 209 J/g.
Q₃ = 120175 J = 120,17 kJ.
Q = Q₁ + Q₂ + Q₃ = -963,8 kJ.
Answer:
They might not be bringing in enough oxygen from the air. It's hard to play soccer if you don't have enough oxygen in your cells. They might not be breaking down starch to make glucose.
Explanation:
