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NeX [460]
4 years ago
12

What is the mass of a light bulb

Chemistry
1 answer:
DIA [1.3K]4 years ago
3 0
It is completely dependent on the type of light bulb you are talking about. There are many different kinds of light bulbs, I cant give you a solid answer.
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When a protein of 50 nanometers is mixed with water the opaque result is called a(n):_____.
12345 [234]

When a protein of 50 nanometers is mixed with water, the opaque result is called a: suspension.

A suspension is a heterogeneous combination of two or extra substances. In it, the particles are suspended for the duration of the solution in bulk and can be easily viewed by means of bare eyes.

Learn more about suspension here:

brainly.com/question/17650174

#SPJ4

3 0
1 year ago
What is the empirical formula for a substance that contains 3.730% hydrogen, 44.44% carbon, and 51.83% nitrogen by mass?\?
Vlada [557]

Given data:

Hydrogen (H) = 3.730 % by mass

Carbon (C) = 44.44%

Nitrogen (N) = 51.83 %

This means that if  the sample weighs 100 g then:

Mass of H = 3.730 g

Mass of C = 44.44 g

Mass of N = 51.83 g

Now, calculate the # moles of each element:

# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles

# moles of C = 44.44/12 = 3.703 moles

# moles of N = 51.83/14 = 3.702 moles

Divide by the lowest # moles:

H = 3.730/3.702  = 1

C = 3.703/3.702 = 1

N = 3.702/3.702 = 1

Empirical Formula = HCN

3 0
3 years ago
What is the chemical formula for iron(II) hydroxide?<br> Fe, OH<br> Fe(OH)<br> FeOH<br> 0 FeOH
denpristay [2]
None of the above, it is Fe(OH)2
3 0
4 years ago
Read 2 more answers
A solid piece of aluminum (51.0 g) was added to a solution of sodium hydroxide (84.1 g) in water, A balanced equation for this r
EastWind [94]
M_{Al}=26,98\frac{g}{mol}\\&#10;m=51g\\\\&#10;n=\frac{m}{M_{Al}}=\frac{51g}{26,97\frac{g}{mol}}\approx1,89mol\\\\\\&#10;M_{NaOH}=39,4\frac{g}{mol}\\&#10;m=84,1g\\\\&#10;n=\frac{m}{M_{NaOH}}=\frac{84,1g}{39,4\frac{g}{mol}}\approx2,14mol

<span>2 NaOH(aq)+ 2 Al(s)+ 2 H</span>₂<span>O → 2 NaAlO</span>₂<span>(aq)+ 3 H</span>₂<span>(g)
</span>  2mol      :     2mol           :                                  3mol
2,14mol   :     1,89mol      :                                  2,835mol
remains         completely consumed
2,14-1,89=0,25mol


A) Al

B)  

M_{NaOH}=39,4\frac{g}{mol}\\&#10;n=0,25mol \Rightarrow \ \ \ m=n*M_{NaOH}=0,25mol*39,4\frac{g}{mol}=9,85g

C)
n=2,835mol\\&#10;M_{H_{2}}=2,02\frac{g}{mol} \Rightarrow \ \ \ m=n*M_{H_{2}}=2,835mol*2,02\frac{g}{mol} \approx 5,73g

7 0
3 years ago
What are 3 examples of pairs of atoms with polar covalent bonds?​
mezya [45]

Answer:

Water - H2O

Ammonia - NH3

Sulfur dioxide - SO2

Hydrogen sulfide - H2S

Ethanol - C2H6O

Explanation:

Those are some atoms with polar covalent bonds. Hope this helps!!

8 0
4 years ago
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