Answer:
Part 1) <em>Sphere</em> The surface area is equal to
and the volume is equal to ![V=\frac{1,372}{3}\pi\ m^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%2C372%7D%7B3%7D%5Cpi%5C%20m%5E%7B3%7D)
Part 2) <em>Cone</em> The surface area is equal to
and the volume is equal to ![V=\frac{112}{3}\pi\ units^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B112%7D%7B3%7D%5Cpi%5C%20units%5E%7B3%7D)
Part 3) <em>Triangular Prism</em> The surface area is equal to
and the volume is equal to ![V=17.388\ mm^{3}](https://tex.z-dn.net/?f=V%3D17.388%5C%20mm%5E%7B3%7D)
Step-by-step explanation:
Part 1) The figure is a sphere
a) Find the surface area
The surface area of the sphere is equal to
![SA=4\pi r^{2}](https://tex.z-dn.net/?f=SA%3D4%5Cpi%20r%5E%7B2%7D)
we have
----> the radius is half the diameter
substitute
![SA=4\pi (7)^{2}](https://tex.z-dn.net/?f=SA%3D4%5Cpi%20%287%29%5E%7B2%7D)
![SA=196\pi\ m^{2}](https://tex.z-dn.net/?f=SA%3D196%5Cpi%5C%20m%5E%7B2%7D)
b) Find the volume
The volume of the sphere is equal to
![V=\frac{4}{3}\pi r^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E%7B3%7D)
we have
----> the radius is half the diameter
substitute
![V=\frac{4}{3}\pi (7)^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%287%29%5E%7B3%7D)
![V=\frac{1,372}{3}\pi\ m^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%2C372%7D%7B3%7D%5Cpi%5C%20m%5E%7B3%7D)
Part 2) The figure is a cone
a) Find the surface area
The surface area of a cone is equal to
![SA=\pi r^{2} +\pi rl](https://tex.z-dn.net/?f=SA%3D%5Cpi%20r%5E%7B2%7D%20%2B%5Cpi%20rl)
we have
![r=4\ units](https://tex.z-dn.net/?f=r%3D4%5C%20units)
![h=7\ units](https://tex.z-dn.net/?f=h%3D7%5C%20units)
Applying Pythagoras Theorem find the value of l (slant height)
![l^{2}=r^{2} +h^{2}](https://tex.z-dn.net/?f=l%5E%7B2%7D%3Dr%5E%7B2%7D%20%2Bh%5E%7B2%7D)
substitute the values
![l^{2}=4^{2} +7^{2}](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D4%5E%7B2%7D%20%2B7%5E%7B2%7D)
![l^{2}=65](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D65)
![l=\sqrt{65}\ units](https://tex.z-dn.net/?f=l%3D%5Csqrt%7B65%7D%5C%20units)
so
![SA=\pi (4)^{2} +\pi (4)(\sqrt{65})](https://tex.z-dn.net/?f=SA%3D%5Cpi%20%284%29%5E%7B2%7D%20%2B%5Cpi%20%284%29%28%5Csqrt%7B65%7D%29)
![SA=16\pi +4\sqrt{65}\pi](https://tex.z-dn.net/?f=SA%3D16%5Cpi%20%2B4%5Csqrt%7B65%7D%5Cpi)
![SA=(16+4\sqrt{65})\pi\ units^{2}](https://tex.z-dn.net/?f=SA%3D%2816%2B4%5Csqrt%7B65%7D%29%5Cpi%5C%20units%5E%7B2%7D)
b) Find the volume
The volume of a cone is equal to
![V=\frac{1}{3}\pi r^{2}h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E%7B2%7Dh)
we have
![r=4\ units](https://tex.z-dn.net/?f=r%3D4%5C%20units)
![h=7\ units](https://tex.z-dn.net/?f=h%3D7%5C%20units)
substitute
![V=\frac{1}{3}\pi (4)^{2}(7)](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20%284%29%5E%7B2%7D%287%29)
![V=\frac{112}{3}\pi\ units^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B112%7D%7B3%7D%5Cpi%5C%20units%5E%7B3%7D)
Part 3) The figure is a triangular prism
a) The surface area of the triangular prism is equal to
![SA=2B+PL](https://tex.z-dn.net/?f=SA%3D2B%2BPL)
where
B is the area of the triangular base
P is the perimeter of the triangular base
L is the length of the prism
<em>Find the area of the base B</em>
![B=\frac{1}{2} (2.7)(2.3)=3.105\ mm^{2}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B1%7D%7B2%7D%20%282.7%29%282.3%29%3D3.105%5C%20mm%5E%7B2%7D)
<em>Find the perimeter of the base P</em>
![P=2.7*3=8.1\ mm](https://tex.z-dn.net/?f=P%3D2.7%2A3%3D8.1%5C%20mm)
we have
![L=5.6\ mm](https://tex.z-dn.net/?f=L%3D5.6%5C%20mm)
substitute the values
![SA=2(3.105)+(8.1)(5.6)=51.57\ mm^{2}](https://tex.z-dn.net/?f=SA%3D2%283.105%29%2B%288.1%29%285.6%29%3D51.57%5C%20mm%5E%7B2%7D)
b) Find the volume
The volume of the triangular prism is equal to
![V=BL](https://tex.z-dn.net/?f=V%3DBL)
where
B is the area of the triangular base
L is the length of the prism
we have
![B=3.105\ mm^{2}](https://tex.z-dn.net/?f=B%3D3.105%5C%20mm%5E%7B2%7D)
![L=5.6\ mm](https://tex.z-dn.net/?f=L%3D5.6%5C%20mm)
substitute
![V=(3.105)(5.6)=17.388\ mm^{3}](https://tex.z-dn.net/?f=V%3D%283.105%29%285.6%29%3D17.388%5C%20mm%5E%7B3%7D)