All categories

4 years ago

Which of these points lies on the line described by the equation below? y - 4 = -2(x - 6)

1 answer:

3 0

Y - y₁ = m(x - x₁)
y - 4 = -2(x - 6)
y - 4 = -2(x) + 2(6)
y - 4 = -2x + 12
+ 4 + 4
y = -2x + 16

The answer is D, (6, 4).

You might be interested in

What is the cube root of -0.216?<br>

timofeeve [1]

Answer:

-0.6

Step-by-step explanation:

6 0

3 years ago

A soccer team is having a car wash the team spent $75 on supplies and $260 including tips....

Elena L [17]

It is 185 after paying for the supplied

7 0

4 years ago

If 18-6x is 4 less than -8, what is the value of -3x?

UNO [17]

Answer:

-15

Step-by-step explanation:

x=5

4 0

4 years ago

Read 2 more answers

8 1/4 minus 5/6 equals what??

kondaur [170]

Ok to figure it out you first find the common factor, which is 12
so the fractions become 8 3/12 and 10/12 then you subtract those 2,
8 3/12-10/12 is 7 5/12.
Hope That Helps!!!

6 0

4 years ago

Find the equation of the axis of symmetry of the following parabola algebraically.

mr Goodwill [35]

Answer:

the equation of the axis of symmetry is $x=8$

Step-by-step explanation:

Recall that the equation of the axis of symmetry for a parabola with vertical branches like this one, is an equation of a vertical line that passes through the very vertex of the parabola and divides it into its two symmetric branches. Such vertical line would have therefore an expression of the form: $x=constant$ , being that constant the very x-coordinate of the vertex.

So we use for that the fact that the x position of the vertex of a parabola of the general form: $y=ax^2+bx+c$ , is given by:

$x_{vertex}=\frac{-b}{2\,a}$

which in our case becomes:

$x_{vertex}=\frac{-b}{2\,a} \\x_{vertex}=\frac{48}{2\,(3)} \\x_{vertex}=\frac{48}{6} \\x_{vertex}=8$

Then, the equation of the axis of symmetry for this parabola is:

$x=8$

4 0

4 years ago