Answer:
a(n)=1.15[a(n-1)]
Step-by-step explanation:
we know that
Let
a0 -----> the length of the original copy
<em>The first copy is equal to</em>
a1=1.15(a0)
<em>The second copy is </em>
a2=1.15[1.15(a0)] or a2=1.15[a1]
<em>The third copy is</em>
a3=1.15{1.15[1.15(a0)]} or a3=1.15[a2]
therefore
A recursive formula will be
a(n)=1.15[a(n-1)]
Answer: The probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.
Explanation:
Step 1: Estimate the standard error. Standard error can be calcualted by dividing the standard deviation by the square root of the sample size:
So, Standard Error is 0.08 million or $80,000.
Step 2: Next, estimate the mean is how many standard errors below the population mean $1 million.
-6.250 means that $1 million is siz standard errors away from the mean. Since, the value is too far from the bell-shaped normal distribution curve that nearly 100% of the values are greater than it.
Therefore, we can say that because 100% values are greater than it, probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.
Answer:
Step-by-step explanation: 11/12 - 3/8
1. First, we will find a common denomenator. It needs to be the least common factor, or the answer will not be in its simplist form. Let's take a look at the multiples of 12 and 8.
12: 12, 24, 36, 48, 60, 72, 84, 96
8: 8, 16, 24, 32, 40, 48, 56, 64, 72
2. Next, we will choose the smallest common multiple. That would be 24.
3. Now, we will work this out.
11/12 = 22/24
3/8 = 9/24
4. Subtract.
22/24 - 9/24
= 13/24
=
I found the denomenators by multiplying.
Hope this answer helped!