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horrorfan [7]
3 years ago
6

Find the missing length

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

{tv}^{2} =  {48}^{2}  +  {24}^{2} \\   {tv}^{2}  = 2880 \\ tv =  \sqrt{2880}  = 53.66

TV + VS = missing length

53.66 +39 = missing length

Missing length = 92.66

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pantera1 [17]

Answer:

The wall is 15 FT tall

Step-by-step explanation:

Add 5 and 10

8 0
3 years ago
Need help with these problems and I have to show my work
Rasek [7]

Answer:

1. 20 min and 15 sec

2. 4 min and 30 sec

3. y=80x-20

4. the second one

Step-by-step explanation:

1.  in 2 min you have 25 g

in 15 sec you loose 2.5 g

2. in 4 min you have 5 g

in 30 sec you loose 5 g

3. y=45x-10

   y=80x-20

4. it takes 2 min and 15 sec to empty the first one and 3 min to empty the second one.

8 0
3 years ago
the probability that an international flight leaving the united states is delayed in departing (event d) is .36. the probability
melomori [17]

Answer:

                     \large\boxed{\large\boxed{0.36}}

Explanation:

This is a typical problem of conditional probability.

In this case you know:

  • the probability of the event D <em>(an international flight leaving the U.S. is delayed in departing</em>), which is 0.36 and you can write as P(D) = 0.36

  • the probability of event P <em>(an international flight leaving the U.S.  is a transpacific flight</em>), which is 0.25 and you can write as P(P) = 0.25;

  • the joint probability of event P and D (<em>international flight leaving the U.S. is a transpacific and is delayed in departing</em>), which is 0.09 and you can write as P (P ∩ D) = 0.09.

You need to determine the <em>probability that an international flight leaving the United States is delayed given that the flight is a transpacific flight</em>, i.e. the conditional probability P (D/P).

Hence, use the formula for conditional probability:

  • P (D/P) = P (D ∩ P) / P(D) = P (P ∩ D) / P (D)

  • P (D/P) = 0.09 / 0.25 = 0.36
5 0
4 years ago
What is 4.284 rounded to 2 significant digits.
kolezko [41]

Step-by-step explanation:

4.284

≈4.3

Hope it helps ya

3 0
3 years ago
Two congruent right triangles with sides of 3, 4, 5 are placed together so that one pair of corresponding sides touch and the re
Rom4ik [11]
It depends on which pair of the sides are touched.. if the 4s are touched then the perimeter would be 5+5+3+3=16, if the 3s are touched then the perimeter would be 5+5+4+4=18 but if the 5s are touched then it becomes a rectangle so that's irrelevant
8 0
4 years ago
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