(100+3-4(4-5))/(6+5+5+5+300)
=(100+3-16+20)/(321)
=(107)/(321)
=1/3
Hope it helps : )
The tower is 61.65 meters tall.
<u>SOLUTION:
</u>
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,

Then, (let it be) n meter tall
36.25 long shadow
So, by cross multiplication method,

This can be written as,

Cross multiplications steps: (To find Single Variable)
- Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
- Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
- Set the two products equal to each other.
- Solve for the variable.
Answer:
The value of f(3) is 8 ⇒ D
Step-by-step explanation:
- In the function f(x) = y, y is the corresponding value of x
- Ex: If f(a) = b, then the value of y = b at x = a
Let us solve the question
∵ The given figure represents the function f(x)
→ That means every point on the graph represents f(x) = y
∴ f(x) = y
∵ We need to find f(3)
→ That means we need the value of y at x = 3
∴ x = 3
Look at the graph and find the y-coordinate of the point that lies on the curve and has x-coordinate = 3
→ Each small square on the x-axis represents 1 unit, and on the y-axis
represents 2 units
∵ There is a point on the graph that has x-coordinate = 3
∵ The y-coordinate of this point is 8
∴ The point (3, 8) lies on the graph of f(x)
∴ x = 3 and y = 8
∴ f(3) = 8
∴ The value of f(3) is 8
Answer:
Total surface area of the given figure is 246.75 square mile.
Step-by-step explanation:
Surface Area of the given figure = Lateral surface area + Area of the base
Lateral surface area of the figure = Sum of the areas of 5 triangular surfaces
= 
= 
= 162.75 mi²
Surface area of the pentagonal base = 84 mi²
Total surface area of the figure = 162.75 + 84
= 246.75 mi²
Therefore, total surface area of the given figure is 246.75 square mile.
Answer:
Michael's present age = p + 5
Michael's present age = 3p + 15
Sum of there ages 6 year age = 5p + 38
Sum of there ages 3 year ago = 5p - 11
Step-by-step explanation:
Assume;
Age of Rui Feng = x
Age of Micheal = x + 5
Age if Vishal = 3[x+5]
Given:
Age of Rui Feng = P
Computation:
Michael's present age = Age of Rui Feng + 5
Michael's present age = p + 5
Vishal's present age = 3[p + 5]
Michael's present age = 3p + 15
Sum of there ages 6 year age = [p + 6] + [p + 5 + 6] + 3[p + 5] + 6
Sum of there ages 6 year age = 5p + 38
Sum of there ages 3 year ago = [p - 3] + [p + 5 - 3] + 3[p + 5] - 3
Sum of there ages 3 year ago = 5p - 11