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alexira [117]
3 years ago
14

Find the equation of the line passing through the point (–1, –2) and perpendicular to the line y = –1∕2x + 5. Question options:

A) y = –1∕2x – 5∕2 B) y = 1∕2x – 5∕2 C) y = 2x D) y = –1∕2x
Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

<h3>The answer is option C</h3>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question

y = - 1/2x + 5

Comparing with the general equation above

Slope / m = -1/2

Since the lines are perpendicular to each other the slope of the other line is the negative inverse of the original line

That's

Slope of the perpendicular line = 2

Equation of the line using point (–1, –2) and slope 2 is

y + 2 = 2( x + 1)

y + 2 = 2x + 2

y = 2x + 2 - 2

We have the final answer as

<h3>y = 2x</h3>

Hope this helps you

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