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3 years ago

11

Solve: 110°20'

2 answers:

GuDViN [60]3 years ago

7 0

Answer:

110 1/3 or 100.33 degrees (to the nearest hundredth).

Step-by-step explanation:

There are 60 ' (minutes) in a degree.

So 20' = 20/60 = 1/3 of a degree.

worty [1.4K]3 years ago

3 0

Answer:

110 1/3°

Step-by-step explanation:

Recall that 1° = 60'. Then 20' is 1/3 of 1°, or (1/3)°.

Then 110° 20' = 110° + (1/3)° = 110 1/3°.

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Write a number sentence that compares 58,219 and 58,231

professor190 [17]

Answer:

<em>58,219 < 58,231</em>

Step-by-step explanation:

58,219 is less than 58,231, so the sentence is

58,219 < 58,231

8 0

3 years ago

Read 2 more answers

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago

3) g(x)= x3 + x<br> h(x) = x + 4<br> Find g(0)h(0)

Arte-miy333 [17]

Answer:

$goh(x)=x^3+12x^2+49x+68$

Step-by-step explanation:

$g(x) = x^3+x$

$h(x)=x+4$

We have to find

$goh(x)$

$goh(x) = g(h(x))=g(x+4)$

If $g(x) = x^3+x$

$g(x+4) = (x+4)^3+(x+4)$

= $x^3+12x^2+49x+68$

Hence our answer is

$goh(x)=x^3+12x^2+49x+68$

4 0

3 years ago

A teacher surveyed her class to find out how many texts the students send in a week. She created this box plot to show the data.

Marta_Voda [28]

Answer: 130
Explanation:

7 0

3 years ago

Energy Basics:Question 1

marin [14]

Answer:

B and C, only

Step-by-step explanation:

5 0

3 years ago