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3 years ago

Three terms of an arithmetic sequence are shown below. Which recursive formula defines the sequence?

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

3 0

f (n + 1) = f(n) + 2 so c is the answer

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Write an explicit formula for an the nth term of the sequence 7,3, 1,....

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3 years ago

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Step-by-step explanation:

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3 years ago

Log 5 +3 log 2-log4÷log10

allsm [11]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's simplify step-by-step.

$Log (5) + (3 log (2)) - \frac{log(4)}{log(10)}$

$= 0.69897 + 3(log (2)) - \frac{log (4)}{log (10)}$

$= 0.69897 + (3) (0.30103) - \frac{log (4)}{log(10)}$

$= 0.69897 + 0.90309 - \frac{log (4)}{log(10)}$

$= 1.60206 - \frac{log(4)}{log(10)}$

$= 1.60206 - \frac{1.60206}{log (10)}$

$= 1.60206 - \frac{1.60206}{1}$

$= 1.60206 - 0.60206$

$= 1$

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

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Have a great day/night!

❀*May*❀

4 0

3 years ago

Subtract the sum of (3/5+1/5i) and (4/5-2/5i) from (9/5-1/5i). The result is

olga_2 [115]

Subtract the sum of (3/5+1/5i) and (4/5-2/5i) from (9/5-1/5i).
The sum will be:
(3/5+1/5i)+(4/5-2/5i)
=(3/5+4/5)+(1/5i-2/5i)
=7/5-1/5i
subtracting the results we get:
(9/5-1/5i)-(7/5-1/5i)
=(9/5-7/5)+(-1/5i+1/5i)
=2/5+0
=2/5
Answer: 2/5

7 0

3 years ago