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Citrus2011 [14]
3 years ago
13

Mark said he can decompose

alt=" \frac{5}{6} " align="absmiddle" class="latex-formula"> into three fractions with three different numerators and the same denominator. Is this possible? Explain. Remember, you can use equivalent fractions
Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0
You can always make an equivalent fraction by multiplying both the numerator and denominator by 2. If your starting fraction is not already fully simplified, you can divide both by 2 until you have it down to a simplified form. But, with the provided fraction, you can make equivalents and decompose it successfully.
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What is greater 7/10 or 3/6? please show work
vovikov84 [41]
What you need to do is make sure the denominators are the same so multiply 7/10 by 6. It should now be 42/60. Next multiply 3/6 by 10. It should now equal 30/60. 7/10 = 42/60. 3/6 = 30/60. 7/10 is greater. I hope this was somewhat helpful :3
3 0
3 years ago
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Which algebraic expression represents “the sum of a number and 9”?
Marta_Voda [28]

Answer:

B

Step-by-step explanation:

sum means addition so n plus 9 would give you the sum of the both

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3 years ago
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In​ January, each of 70 people purchased a ​$500 washing machine. In​ February, 10​% fewer customers purchased the same washing
aniked [119]

Answer:

Step-by-step explanation:you just subtract or multiply the percent

7 0
3 years ago
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
Allen is given three lengths of rope: 4 feet, 8 feet, and 15 feet. Can Allen form a triangle with side lengths of 4 feet, 8 feet
vesna_86 [32]
No, he cannot ~ 8+4=12; 12 < 15
3 0
3 years ago
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