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nikklg [1K]
3 years ago
8

Which of the following processes rearranges atoms into new molecules during a reaction?

Chemistry
1 answer:
Andreyy893 years ago
4 0
C burning
Because melting is incorrect lol
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In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)?
Anastaziya [24]

Answer: In metallic bonds, the mobile electrons surrounding the positive ions are called <u><em>dipole</em></u>.

6 0
3 years ago
A block of ice is cooled from -0.5 degrees Celsius to -10.1 degrees Celsius. Calculate the temperature change, delta T, in degre
ss7ja [257]
Delta T= T final - T initial
Tfinal= -101.1 °C
Tinitial= -0.5 °C
•Delta T = -101.1°C - (-0.5°C)
=100.6°C

Kelvin= °C + 273
= -100.6 + 273
= 172.4 Kelvin
3 0
2 years ago
A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t
andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)

So, moles of product formed are calculated as follows.

\frac{3}{2} \times 0.17 mol \\= 0.255 mol

Hence, the given data is as follows.

n_{1} = 0.17 mol,      n_{2} = 0.255 mol

V_{1} = 19.5 L,         V_{2} = ?

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

8 0
2 years ago
What letter represents the enthalpy of reaction?
Anna35 [415]

Answer:

Option D. T

Explanation:

Enthalpy change (ΔH) is simply the difference between the heat content of the product (Hp) and the heat content of the reactant (Hr). Mathematically, it is expressed as:

Enthalpy change (ΔH) = Heat of product (Hp) – heat of reactant (Hr)

ΔH = Hp – Hr

From the diagram given above, the difference between the heat content of product and the heat content of reactant is T.

Therefore, the enthalpy change of the reaction is T.

5 0
3 years ago
For each reaction below, use the drop-down menus to select which compound will form a precipitate. Note: It is possible that no
Dimas [21]

Answer:

1. Cadmium sulfide

2. Iron (III) hrydroxide

3. Barium carbonate

8 0
2 years ago
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