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tatiyna
2 years ago
10

How many calories are in a dinner containing 3.5x10 ^6 joules

Chemistry
1 answer:
Scorpion4ik [409]2 years ago
5 0

Answer:

3500000 try this i think it's right not sure

Explanation:

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suppose you wanted to compare two different stain removers to learn which one was better at removing food stains from clothing.
Dovator [93]

Answer:

The amount/type of stain

Explanation:

You would want to ensure that the stain was the same in both samples.  

8 0
1 year ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
weqwewe [10]

Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

5 0
2 years ago
Calculate the ph of a buffer that is 0.13m in lactic acid and 0.10m in sodium lactate.
Alona [7]
According to Henderson–Hasselbalch Equation,

                                       pH  =  pKa + log [Lactate] / [Lactic Acid]
As,
      Ka of Lactic Acid  =  1.38 × 10⁻⁴

           pKa  = -log Ka
           pKa  = -log 1.38 × 10⁻⁴
           pKa  =  3.86
So,
                                  pH  =  3.86 + log [0.10] / [0.13]

                                  pH  =  4.74 + log 0.769

                                  pH  =  4.74 - 0.11

                                  pH  =  4.63
3 0
3 years ago
An industrial chemist is studying a sample of an unknown metal. Describe two ways he could change the metal physically and two w
Illusion [34]

Answer:idk what they cpuld do but we can say this is the right answer :))))

Explanation:

I need PoInTs

5 0
3 years ago
How do you find wave length
Vinil7 [7]

Answer:

If you want to calculate the wavelength of a wave, then all you have to do is plug the wave's speed and wave's frequency into the equation. Dividing speed by frequency gives you the wavelength

Explanation:

4 0
3 years ago
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