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4 years ago

14

A train travels 120 miles in one hour. what is its speed in miles per minute

1 answer:

Eddi Din [679]4 years ago

8 0

Since 1 hour = 60 minutes,
Hence, 120 miles/hour = 120 miles / 60 minutes = 2 miles/minute

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What is (14,-12) translated 6 units left

marissa [1.9K]

Going to the right or left when doing translation effects the x coordinate. In this case, the x coordinate is 14. Since we are moving 6 units to the left, we must subtract 6 from 14. Moving to the left is negative and moving to the right is positive.

14 - 6 = 8

The answer is (8,-12)

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4 years ago

write an expression for the calculation the difference of 35 and 7 divided by the difference of 9 and 2

Rudik [331]

Answer:

35-7/ 9-2

28/7

4

Step-by-step explanation:

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3 years ago

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3 years ago

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storchak [24]

Answer:

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true

Step-by-step explanation:

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3 years ago

A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10

kompoz [17]

Answer:

0.3888

Step-by-step explanation:

To solve the exercise we need a neutral time, so we define at 12:00 as time 0.

If the man arrives in a uniformly distributed time between 11:40 and 12:10, the time is distributed from -20 to 10.

If the woman arrives in a time evenly distributed between 11:45 and 12:20, the time is distributed from -15 to 20.

Assuming that each one arrives at 12: X and 12: Y for men and women, then the space of our time is defined as

Man [-20,10]

Woman [-15,20]

So,

$f_x(x)=\frac{1}{10-(-20)}=\frac{1}{30}\\f_y(y)=\frac{1}{20-(-15)}=\frac{1}{35}$

Then,

$f_{xy}(x,y)=f_x(x)f_y(y)=\frac{1}{30} \frac{1}{35} = \frac{1}{1050}$

The probability of finding an arrival less than 5 minutes is

$P(|X-Y|\leq 5) = \int\limit^20_{-15} \int\limit^{x+5}_{x-5} f(x,y)dydx$

$P(|X-Y|\leq 5)= \frac{1}{1050}\int\limit^{20}_{-15} y|^{x+5}_{x-5}dx$

$P(|X-Y|\leq 5)= \frac{35*10}{900}=0.3888$

6 0

3 years ago