20) A jar filled with only dimes and quarters contains a total of 23 coins. The value of all the coins in

Mathematics

1 answer:

nignag [31]3 years ago

8 0

Answer:

6 quarters

Step-by-step explanation:

6 quarters = 1.50

So that would leave 17 dimes left

And 17 dimes left equal 1.70

1.50 + 1.70 = 3.20

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What two numbers add to 8 and multiply to 28

anygoal [31]

Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula

x+y=8
xy=28

x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0

if you have
ax^2+bx+c=0 then x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28

x= $\frac{-(-8)+/- \sqrt{(-8)^{2}-4(1)(28)} }{2(1)}$
x= $\frac{8+/- \sqrt{-48} }{2}$
x= $\frac{8+/- 4 \sqrt{-3} }{2}$
x= $4+/- 2 \sqrt{-3}$
x= $4+/- 2i \sqrt{3}$
there are no real numbers that satisfy this

5 0

3 years ago

Can you please help me

max2010maxim [7]

Here’s the answer and each step I took to solve it. With the example I made on the side just continue to repeat that for each one to get the answers. You just replace that one number for the X to take the place for the next X value as you go down the table solving them.