All categories

2 years ago

Solve. 5 (4 - x) = 20 - 5x

Mathematics

2 answers:

julia-pushkina [17]2 years ago

4 0

$20 - 5x = 20 - 5x \\ 0$
I think this help, i'm not sure

Doss [256]2 years ago

3 0

First you would want to distribute the 5 into the parentheses
20-5x=20-5x

Then you will see that this statement is true
The statement is true since both sides are identical

Hope this helps! :3

You might be interested in

What is 2/3 -1/5 (fractions)

butalik [34]

Answer:

7/15

Step-by-step explanation:

8 0

2 years ago

2 Emma buys 33 yards of blue fabric and some yellow fabric at a store. She buys a total of 53 yards of fabric. The equation 1 2

Rus_ich [418]

Step-by-step explanation:

your answer is 99

6 0

2 years ago

2,3,5,9,17,33 what are the next three terms?

stich3 [128]

The next three terms of sequence are 65, 129 and 257

Solution:

Given sequence is:

2, 3, 5, 9, 17, 33

We have to find the next three terms in sequence

Let us find the logic used in this sequence

$2 + 2^0 = 2 + 1 = 3\\\\3 + 2^1 = 3 + 2 = 5\\\\5 + 2^2 = 5 + 4 = 9\\\\9 + 2^3 = 9 + 8 = 17\\\\17 + 2^4 = 17 + 16 = 33$

Thus the sequence is increasing by 2 raised to power 0, 1, 2 and so on

Thus the next three terms are found by:

$33 + 2^5 =33 + 32= 65\\\\65 + 2^6 = 65 + 64 = 129\\\\129 + 2^7 = 129 + 128 = 257$

Thus the next three terms of sequence are 65, 129 and 257

3 0

2 years ago

Write an expression to describe the sequence 35, 36, 37.....

lyudmila [28]

Answer:

Step-by-step explanation:

start with 35 and add 1 repeatedly.

7 0

2 years ago

Read 2 more answers

The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t

astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)= $\frac{ME*\sqrt{N}}{s }$ where

Me is the margin of error from the mean

s is the standard deviation of the population

N is the sample size

z(p)= $\frac{8*\sqrt{30}}{50 }$ ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

z(p)= $\frac{8*\sqrt{50}}{50 }$ ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

z(p)= $\frac{8*\sqrt{100}}{50 }$ ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

Minimum required sample size for 0.95 probability is

N≥ $(\frac{z*s}{ME} )^2$ where

N is the sample size

z is the corresponding z-score in 95% probability (1.96)

s is the standard deviation (50)

ME is the margin of error (8)

then N≥ $(\frac{1.96*50}{8} )^2$ ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0

3 years ago