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salantis [7]
3 years ago
11

PLEASE HELP!! I will give brainliest!!

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

See screenshot attached that shows it is correct

Step-by-step explanation:

f(x) has a domain of (-infinity, 6) U (6, infinity). Horizontal asymptote of y= -2

g(x) has a domain of (-infinity, -3) U (-3,2) U (2,infinity). Horizontal asymptote of y=1.

h(x) has a domain of (-infinity, 6) U (6, infinity). Function has a oblique asymptote.

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Belinda runs 8 kilometers in 60 minutes at this how long would it take her to run 2 kiloneters?
sasho [114]

Answer:

It will take Belinda 15 minutes to run 2 kilometers.

Step-by-step explanation:you first divide 8 by 2, which equals 4 and 60 divided by 2 which equals 30. Then you divide 4 by 2 and divide 30 by 2 which will give you the answer of 15 minutes to run 2 kilometers.


3 0
3 years ago
22/5 in simplest form
seraphim [82]
22/5 in simplest form is 4 2/5 because 22/5 is 4 with a remainder of 2, which is the numerator.
8 0
3 years ago
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Find theoretical probability of the given event when rolling 16 sided game piece P(16)
Kobotan [32]

Answer:

1/16

Step-by-step explanation:

Because there is 16 sides.. and the probability to land on one side is 1/16

3 0
2 years ago
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
What is the factored form of x^2 - 196 ?
Luba_88 [7]
D. (x-14)(x+14)
a negative and a positive multiplied makes a negative outcome so -14•+14=-196. x•x is = to x^2
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