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3 years ago

PLEASE HELP!! I will give brainliest!!

Mathematics

1 answer:

Novay_Z [31]3 years ago

3 0

Answer:

See screenshot attached that shows it is correct

Step-by-step explanation:

f(x) has a domain of (-infinity, 6) U (6, infinity). Horizontal asymptote of y= -2

g(x) has a domain of (-infinity, -3) U (-3,2) U (2,infinity). Horizontal asymptote of y=1.

h(x) has a domain of (-infinity, 6) U (6, infinity). Function has a oblique asymptote.

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What is the sum of two numbers is 45 and theire difference is 5

adelina 88 [10]

Answer:

let the two numbers be x and y

x+y=45(equation 1)

x-y=5(equation 2)

from equation (1) y=45-x(equation 3)

substitute 45-x for y in equation 2

x-(45-x)=5

x-45+x=5

x+x-45=5

2x-45=5

2x=45+5

2x=50

x=50/2

x=25

6 0

3 years ago

A bakery bakes 10 cakes per hour & had 3 from the day before. What equation represents this?

likoan [24]

I can give u the answer for numbers 1 and 2

1. y=10x+3

2. TRUE

3.

6 0

3 years ago

CAN SOMEONE PLEASE HELP ME WITH THESE PEOPLE

vazorg [7]

Inverse of $f(x)=x+2$ is $f^{-1}(x)=x-2$ because

$f(x)=x+2\Rightarrow x=f^{-1}(x)+2\Rightarrow\boxed{f^{-1}(x)=x-2}$

Now $f^{-1}(-5)=-5-2=\boxed{-7}$ .

Hope this helps.

4 0

3 years ago

The number of bacteria present after n generations is represented by the expression below, where i is the initial number of bact

kobusy [5.1K]

Answer:

8000

Step-by-step explanation:

The function is given as:

$P(n)=i \cdot 2^n$

Where I=Initial Population

n=Number of Generations

If $i=10^3$ , we want to determine the population of bacteria when n=3.

$P(3)=10^{3} \cdot 2^3$

$=(10*2)^3 =20^3$

=8000

There will be 8000 bacteria after 3 generations.

4 0

3 years ago

You have 3 dogs and they are playful. You decide that dogs are playful.

nadya68 [22]

Answer:

inductive

Step-by-step explanation:

3 0

3 years ago