The equation may also have one common root or no real roots. This gives the maximum number of points where the parabola<span> intersect as </span>2<span>. ... When that is the case, the twp </span>parabolas<span> intersect at 4 </span>distinct<span> points. The maximum number of points of intersection of </span>two distinct parabolas<span> is 4.</span>
Answer:
Step-by-step explanation:
<u>Simplify the numerator:</u>
- 1/x² + 2/y =
- y/(x²y) + 2x²/(x²y) =
- (2x² + y)/(x²y)
<u>Simplify the denominator:</u>
- 5/x - 6/y² =
- 5y²/(xy²) - 6x/(xy²) =
- (5y² - 6x) / (xy²)
<u>Simplify the fraction:</u>
- (2x² + y)/(x²y) ÷ (5y² - 6x) / (xy²) =
- (2x² + y)/(x²y) × xy² / (5y² - 6x) =
- y(2x² + y) / x(5y² - 6x)
Answer:
56 square units
Step-by-step explanation:
The formula for the area of a triangle of base b and height h is:
A = (1/2)(b)(h)
Here, that area is A = (1/2)(8)(14) = 56 square units