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Fittoniya [83]
3 years ago
7

Please help me with this question! i will give brainiest if correct! (if you show me how to lol i have no idea how)

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

  • y(2x² + y) / x(5y² - 6x)

Step-by-step explanation:

<u>Simplify the numerator:</u>

  • 1/x² + 2/y =
  • y/(x²y) + 2x²/(x²y) =
  • (2x² + y)/(x²y)

<u>Simplify the denominator:</u>

  • 5/x - 6/y² =
  • 5y²/(xy²) - 6x/(xy²) =
  • (5y² - 6x) / (xy²)

<u>Simplify the fraction:</u>

  • (2x² + y)/(x²y) ÷ (5y² - 6x) / (xy²) =
  • (2x² + y)/(x²y) × xy² / (5y² - 6x) =
  • y(2x² + y) / x(5y² - 6x)
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Does anyone understand this one? I am a little lost.
Harlamova29_29 [7]

Answer:

The graph is decreasing

Step-by-step explanation:

Starting at -1,  the graph goes down to its value at 1

The graph is decreasing

6 0
3 years ago
The diagonal of the rectangle is 13 inches, and the side lengths of the triangles are Pythagorean triples. To the nearest tenth,
frosja888 [35]
1) A Pythagorean triples is a set of three integers, a, b, c,  that follow the rule a^2 + b^2 = c^2

2) Assumin c is the diagonal of your rectangle and the hypotenuse of the triangles, you are looking this:

13^2 = a^2 + b^2

=> 169 = a^2 + b^2

Two integer numbers that meet that equality are 5 and 12:

5^2 = 25
12^2 = 144
=> 5^2 + 12^2 = 25 + 144 = 169

 => 13^2 = 5^2 + 12^2

Now that you have the three numbers you know the dimensions of the figure and can calculate the area of the shaded part. I cannot do that for you becasue you did not include the figure.
3 0
3 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
4 years ago
write an inequality or equation for this question. Maria wants to bike 50 miles. she has already biked 28 miles. If she bikes th
abruzzese [7]
50-28=22
22/3= 7.3

Maria will bike for 8 days (rounded up from 7).
6 0
3 years ago
The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0?
MrMuchimi
6x^2 + 23x  - 4 = 0
factorising:-

(6x - 1)(x  + 4 ) = 0

x = 1/6 , - 4
6 0
4 years ago
Read 2 more answers
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