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Roman55 [17]
3 years ago
7

What is the equation of the circle with center (1, 1) that passes through the point (−3, 4)?

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:  (x - 1)² + (y - 1)² = 25

<u>Step-by-step explanation:</u>

The formula for a circle is     (x - h)² + (y - k)² = r²     where

  • (h, k) is the center
  • r is the radius

Typically, you are given the center and the radius.  In this problem, you are given (x, y) so you must plug that into the equation to find r².

Given: (x, y) = (-3, 4)   and   (h, k) = (1, 1)

                       (-3 - 1)² + (4 - 1)² = r²

                         (-4)²    +   (3)²   = r²

                          16      +    9     = r²

                                  25         = r²

Next, input (h, k) and r² into the equation

                  (x - 1)² + (y - 1)² = 25

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Let's solve your equation step-by-step.
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Step 1: Subtract 3x from both sides.
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6 0
3 years ago
For the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bx%7D%20%7D%7B5%7D%20%2B2" id="TexFormula1" title="\f
Ber [7]

Answer:

f^{-1}(x)=25(x-2)^2

Step-by-step explanation:

The inverse function can be found by solving ...

  f(y) = x

  (√y)/5 +2 = x

  (√y)/5 = x -2 . . . . . subtract 2

  √y = 5(x -2) . . . . . . multiply by 5

  y = 25(x -2)² . . . . . square both sides

The inverse function is ...

  f^{-1}(x)=25(x-2)^2

_____

<em>About the graph</em>

The inverse of a function is its mirror image across the line y = x.

4 0
4 years ago
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