Find the value of x in the isosceles trapezoid below?
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Answer:
A
Step-by-step explanation:
Given
y = 2x² - 3x + 1
To find the zeros let y = 0, that is
2x² - 3x + 1 = 0
Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × 1 = 2 and sum = - 3
The factors are - 2 and - 1
Use these factors to split the x- term
2x² - 2x - x + 1 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) - 1(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x - 1) = 0
Equate each factor to zero and solve for x
2x - 1 = 0 ⇒ 2x = 1 ⇒ x =
x - 1 = 0 ⇒ x = 1