I think it's 36. Because 7x3=21 and 12x3=36
The piecewise function all the way to the left (x + 3) should have an ending point shaded in. [At x = -2] The next function ((x^2) -1) should have both ending points left unshaded. Finally, the logarithm function should have a shaded in starting point [At x = 1] and should have an unshaded ending point at x = 3.
Answer:
False
Step-by-step explanation:
In order to perform matrix multiplication, the number of columns in the first matrix must be the same as the number of rows in the second matrix.
In this case, the number of columns in the first matrix is 5 and the number of rows in the second column is 3 therefore they aren't the same value, hence, cannot be multiplied
Their combined weight would be 7 2/14. here are the steps of how I got my answer.
1. I made the answers into improper fractions. 3 1/2= 7/2 and 4 1/7= 29/7.
2. then I found the least common multiple (LCM) of 2 and 7 which is 14.
3. next in order to make both denominators become 14 I cant just make 7/2 into 7/14 and 29/7 into 29/14. so I multiplied 29/7 by 2 which got me 58/14 and 7/2 by 7 which got me 42/14.
4. then I did 42/14+ 58/14= 100/14.
5. Then the last step was to make the improper fraction 100/14 into a proper fraction. Now how do you do that? BY DIVIDING! I divided 100 by 14 and I got my answer of 7 2/14.
Hope this helped! :)
Starting from
take the first derivative using the power and chain rules:
Now take the second derivative:
Optionally, you can condense the second derivative a bit by factoring out 
, which gives
