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igor_vitrenko [27]
3 years ago
10

How many mangoes were originally in the bowl

Mathematics
1 answer:
nikklg [1K]3 years ago
5 0
6 because 1 in 1/6 represents how many he took and the denominator in the other fractions gets smaller because it's less and less each time
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Jennie can make 7 quilts with 21 yards of material how many yards of material would be required to make 12 quilts ?
larisa [96]
I think it's 36. Because 7x3=21 and 12x3=36
4 0
3 years ago
Please help I’ll give brainliest
damaskus [11]
The piecewise function all the way to the left (x + 3) should have an ending point shaded in. [At x = -2] The next function ((x^2) -1) should have both ending points left unshaded. Finally, the logarithm function should have a shaded in starting point [At x = 1] and should have an unshaded ending point at x = 3.
6 0
3 years ago
It is possible to multiply a 3 x 5 matrix and a 3 x 5 matrix.<br> O True<br> O False
oksian1 [2.3K]

Answer:

False

Step-by-step explanation:

In order to perform matrix multiplication, the number of columns in the first matrix must be the same as the number of rows in the second matrix.

In this case, the number of columns in the first matrix is 5 and the number of rows in the second column is 3 therefore they aren't the same value, hence, cannot be multiplied

5 0
3 years ago
a single box of thumb tacks weighed 3 1/2 if a teacher had 4 1/7 boxes of thumbtacks how much would their combined weight be?
lana66690 [7]
Their combined weight would be 7 2/14. here are the steps of how I got my answer.
1. I made the answers into improper fractions. 3 1/2= 7/2 and 4 1/7= 29/7.
2. then I found the least common multiple (LCM) of 2 and 7 which is 14.
3. next in order to make both denominators become 14 I cant just make 7/2 into 7/14 and 29/7 into 29/14.  so I multiplied 29/7 by 2 which got me 58/14 and 7/2 by 7 which got me 42/14.
4. then I did 42/14+ 58/14= 100/14.
5. Then the last step was to make the improper fraction 100/14 into a proper fraction. Now how do you do that? BY DIVIDING! I divided 100 by 14 and I got my answer of 7 2/14.

Hope this helped! :)
6 0
3 years ago
Can someone pls help me find the second derivative of this. I need to find the concave up and down intervals but I’m having trou
KonstantinChe [14]

Starting from

f(x)=\dfrac14(x+1)^{\frac83}-4(x+1)^{\frac23}

take the first derivative using the power and chain rules:

f'(x)=\dfrac83\cdot\dfrac14(x+1)^{\frac83-1}-\dfrac23\cdot4(x+1)^{\frac23-1}

f'(x)=\dfrac23(x+1)^{\frac53}-\dfrac83(x+1)^{-\frac13}

Now take the second derivative:

f''(x)=\dfrac53\cdot\dfrac23(x+1)^{\frac53-1}-\left(-\dfrac13\right)\cdot\dfrac83(x+1)^{-\frac13-1}

f''(x)=\boxed{\dfrac{10}9(x+1)^{\frac23}+\dfrac89(x+1)^{-\frac43}}

Optionally, you can condense the second derivative a bit by factoring out \frac89(x+1)^{-\frac43}, which gives

f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^{\frac63}+1\right)

f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^2+1\right)

f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80x^2+160x+81\right)

3 0
3 years ago
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