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lakkis [162]
3 years ago
12

The following measurements were taken of a tree. Do the age and height show direct variation? If so, write the equation of varia

tion.
direct variation y = 0.28x

direct variation y = 0.28x + 3.6

direct variation x = 3.6y

no direct variation

Mathematics
2 answers:
KiRa [710]3 years ago
7 0
Replace the value of x and y into the equations and see if they solve:

x = -5, y = 24

24 = 0.28(-5),  24 = -1.4 False
24 = 0.28(-5) +3.6, 24 = 2.2 False

-5 = 3.6(24), -5 = 86.4 False
 none of the given equations work, so there is no direct variation

Dmitriy789 [7]3 years ago
4 0
Hello!
----------
There is no direct variation in the age and height.
----------
WORK: 0.28*-5= -1.4
             0.28*-5+3.6=2.2
             3.6*24=86.4
----------
Hope this helps and have a great day!
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Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.

Step-by-step explanation:

\frac{r}{4}  = 2.5 \\ lhs =  \frac{r}{4}  \\  =  \frac{10}{4}  \\  = 2.5 \\  = rhs \\  \therefore \:  \frac{r}{4}  = 2.5 \\

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3 years ago
Find the Value of X. If your answer is not an integer, express it in simplest radical form.
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6 0
3 years ago
Savannah gets paid at home for doing extra chores. Last week, she did 3 loads of laundry and 3 loads of dishes, and her parents
Fynjy0 [20]

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7 0
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Anthony works at a clothing store and gets a 15% employee discount.If he purchase p pants and s shirts his total can be found us
IgorC [24]

Answer:

$192.95

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4 0
3 years ago
Laura lives 15 miles east of Kevin’s place. Kevin lives 8 miles south of Michelle’s place. How far does Michelle live from Laura
My name is Ann [436]

Answer:

17 miles.

Step-by-step explanation:

Let's define:

North as the positive y-axis

East as the positive x-axis.

We know that Laura lives 15 miles east of Kevin's place.

Kevin lives 8 miles south of Michelle's place.

So, if we define the origin, (0, 0) as Laura's place.

From:

"that Laura lives 15 miles east of Kevin's place."

We have that the location of Kevin's house is 15 miles west from Laura's place, then Kevin's house is at:

(0, 0) + (-15mi, 0) = (-15mi, 0)

From Kevin lives 8 miles south of Michelle's place, we know that Michelle's live 8 miles north of Kevin's place.

Then the location of Michele's house is the location of Kevin's plus (0, 8mi).

Michelle's house is located at:

(-15mi, 0) + (0, 8mi)  =(-15mi, 8mi)

Now we want to find the distance between Michelle's house and Laura's house.

Michelle's house is at (-15mi, 8mi)

Laura's house is at (0mi, 0mi)

Remember that the distance between two points (a, b) and (c, d) is given by:

D = \sqrt{(a - c)^2 + (b - d)^2}

Then the distance between  (-15mi, 8mi) and (0mi, 0mi) is:

D = \sqrt{(-15mi - 0mi)^2 + (8mi - 0mi)^2} = 17mi

The correct option is the first one, 17 miles.

6 0
3 years ago
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