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lyudmila [28]
3 years ago
9

A recent article found that Massachusetts residents spent an average of $860.70 on the lottery in 2010, more than three times th

e U.S. average (http://www.businessweek.com, March 14, 2012). A researcher at a Boston think tank believes that Massachusetts residents spend significantly less than this amount. He surveys 100 Massachusetts residents and asks them about their annual expenditures on the lottery.
a. Specify the competing hypotheses to test the researcher’s claim. H0: μ = 860.70; HA: μ ≠ 860.70 H0: μ ≥ 860.70; HA: μ < 860.70 H0: μ ≤ 860.70; HA: μ > 860.70
b. Specify the critical value(s) of the test at the 10% significance level. (Negative value should be indicated by a minus sign. Round intermediate calculations to 4 decimal places. Round your answer to 3 decimal places.) Critical value rev: 08_20_2013_QC_33738
c. Compute the value of the appropriate test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to 4 decimal places. Round your answer to 2 decimal places.) Test statistic d. At α = 0.10, what is the conclusion? Reject H0; the average Massachusetts residents spent less than $860.70 on the lottery in 2010 Reject H0; the average Massachusetts residents spent no less than $860.70 on the lottery in 2010 Do not reject H0; the average Massachusetts residents spent less than $860.70 on the lottery in 2010 Do not reject H0; the average Massachusetts residents spent no less than $860.70 on the lottery in 2010 Annual Lottery Expenditures (in $)
790 594 899 1105 1090 1197 413 803 1069 633 712 512 481 654 695 426 736 769 877 777 785 776 1119 833 813 747 1244 1023 1325 719 1182 528 958 1030 1234 833 745 985 774 1002 561 681 546 777 844 856 785 1289 502 703 334 1140 594 719 1002 943 1025 969 576 627 989 915 662 802 876 962 878 668 1227 947 864 1016 1022 723 665 1072 610 538 992 978 1291 1139 1111 873 850 941 845 639 495 1016 939 974 893 645 1098 788 682 686 764 759
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0
JkjkkKkjahzhzjLlJsloUzjsjsjwwnmwmwmwmwmwmwmwmeemekejrjrjrj
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Answer:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:

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The confidence level is 95.44 and the signficance is 1-0.9544=0.0456 and the value of \alpha/2 =0.0228. And the critical value for this case is z = \pm 1.99

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a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

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