Bro how could you not know this it’s 4
Answer:
x = 1 1/4
Step-by-step explanation:
sqrt( 7x+2) = sqrt(3x+7)
Square each side
(sqrt( 7x+2))^2 = (sqrt(3x+7))^2
7x+2 = 3x+7
Subtract 3x from each side
7x-3x +2 = 3x+7-3x
4x+2 = 7
Subtract 2 from each side
4x+2-2 = 7-2
4x = 5
Divide by 4
4x/4 = 5/4
x = 1 1/4
Check for extraneous solution
sqrt( 7*5/4+2) = sqrt(3*5/4+7)
sqrt( 35/4 + 8/4) = sqrt(15/4+28/4)
sqrt( 43/4) = sqrt(43/4)
Solution is valid
Cos(x) = sin(90 - x)
cos(53) = sin(90 - 53)
cos(53) = sin(37)
Answer:
6
Step-by-step explanation:
Its 6 or 4, but leaning toward 6
Given the equation:
We will use the following rule to find the solution to the equation:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
From the given equation: a = 6, b = 7, c = 2
So,
![\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B7%5E2-4%5Ccdot6%5Ccdot2%7D%7D%7B2%5Ccdot6%7D%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B1%7D%7D%7B12%7D%3D%5Cfrac%7B-7%5Cpm1%7D%7B12%7D%20%5C%5C%20x%3D%5Cfrac%7B-7-1%7D%7B12%7D%3D-%5Cfrac%7B8%7D%7B12%7D%3D-%5Cfrac%7B2%7D%7B3%7D%20%5C%5C%20or%2Cx%3D%5Cfrac%7B-7%2B1%7D%7B12%7D%3D-%5Cfrac%7B6%7D%7B12%7D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cend%7Bgathered%7D)
So, the answer will be option B) x = -1/2, -2/3
