F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235
Answer:
b
Step-by-step explanation:
uqawert
According to the information given, the system of inequalities that models the situation is given by:
<h3>System of inequalities:</h3>
For the system, the variables are:
- x is the number of hours that Pump 1 runs.
- y is the number of hours that Pump 2 runs.
They will run for at least 18 hours in a day but obviously no more than 24 hours in a day, hence:


Pump 1 can move 120 gallons per hour while Pump 2 can move 200 gallons per hour. In total the two pumps must move at least 3,000 gallons of water per day, hence:

You can learn more about system of inequalities at brainly.com/question/14361489
Answer:
a peso worth is 5 cent
Step-by-step explanation:
i hope thag helps so 5 all tye ways to 100