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hodyreva [135]
3 years ago
11

Dina and Masha started out on a 20 miles bike path at the same time. When Dina reached the end of the 20 miles, Masha still had

4 miles left to bike. If Dina's biking speed was 10 mph, find Masha's biking speed.
Mathematics
2 answers:
mixas84 [53]3 years ago
7 0

Answer:

8mph

Step-by-step explanation:

when dina arrived to 20 masha was at 16. so the relation is 20/16 and if dina's speed was 10 your formula is 10/x=20/16 that means x/10=16/20. so x will be 8

gogolik [260]3 years ago
4 0

Answer:

8mph

Step-by-step explanation:

(20-4)/2

=16/2

=8

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The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
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nadya68 [22]

Step-by-step explanation:

The first one (f×g)(x) is asking you what is f of x times g of x. This means you multiply the function. You can multiply by the first term (5x) then the second (3) and combine like terms.

{15x}^{2} (5x) =  {75x}^{3}   \\ 19x(5x)  = 95 {x}^{2} \\  6(5x)  = 30x

{15x}^{2} (3) = 45 {x}^{2}  \\ 19x(3) = 57x \\ 6(3) = 18

Combine like terms

{75x}^{3}  +  {95x}^{2}  +  {45x}^{2}  + 30x + 57x \\  + 18 = \\   {75x}^{3}  +  {140x}^{2}  + 87x + 18

The second one asks you to divide.

Factor out f(x):

{15x}^{2}  + 19x + 6

From dividing f(x) /g(x)

\frac{ {15x}^{2} + 19x + 6 }{5x + 3}

To

\frac{(5x + 3)(3x + 2)}{5x + 3}

Cancel like terms since (5x+3) is on top and bottom of fraction.

You get 3x+2

5 0
3 years ago
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