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Andrews [41]
3 years ago
7

which best explains what a secondary source is? a. a text with no connection to history b. a text based on a primary source c. a

text that contains opinions d. a text from a particular period
Mathematics
1 answer:
Ilya [14]3 years ago
5 0
<span>b. a text based on a primary source</span>
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Compute 860 times 500
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Answer:430,000

Step-by-step explanation:

Type it into your calculator and you get that number

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Determine the exact values of the six trigonometric functions of the real number t
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Renna pushes the elevator button, but the elevator does not move. The mass limit for the elevator is 450 kg, but Renna and her l
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Answer:

620-37.4p\leq 450

Step-by-step explanation:

Let p be the number of identical packages.

We have been given that each package has a mass of 37.4 kg, so weight of p packages will be 37.4p.

The total mass of Renna and her load of identical packages is 620 kg.

We have been given that the mass limit for the elevator is 450 kg. This means that Renna can remove p packages from 620 kg such that 620 minus weight of p packages will be less than or equal to 450 kg.

We can represent this information in an inequality as:

620-37.4p\leq 450

Therefore, the inequality 620-37.4p\leq 450 can be used to determine the number of packages, p, Renna could remove from the elevator to meet the mass requirement.

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3 years ago
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How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

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3 years ago
Solve for x , if x + 47 = -23 .<br><br> x =
love history [14]

Answer:

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Step-by-step explanation:

subtract 47 from both sides to get

x = -23 - 47

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