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3 years ago

Question Progress

Mathematics

1 answer:

son4ous [18]3 years ago

6 0

Question:

Sue is thinking of a number 3/8 of 88 = 1/3 of her number

what number is she thinking of

Answer:

$x = 99$

Step-by-step explanation:

Represent the number with x.

So, we have:

$\frac{3}{8} * 88 = \frac{1}{3} *x$

Multiply through by 3

$3 * \frac{3}{8} * 88 = \frac{1}{3} *x * 3$

$3 * \frac{3}{8} * 88 = x$

$3 * 3 * 11 = x$

$99= x$

$x = 99$

Hence, she is thinking of 99

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Find three consecutive even integers so that twice the largest

vekshin1

If x is the smallest of the three, then the next two integers are x + 2 and x + 4.

"Twice the largest is 20 less than the sum of all three" translates to

2 (x + 4) = (x + (x + 4) + (x + 6)) - 20

Solve for x :

2x + 8 = 3x - 10

x = 18

Then the three numbers are {18, 20, 22}.

7 0

3 years ago

Read 2 more answers

Help!! Can someone explain this to me I’m not getting it.

chubhunter [2.5K]

Answer:

A. 99 sq cm

Step-by-step explanation:

Area of geometric shape

= 2 times the area of one triangle with base a and height c

+ 2 times the area of one triangle with base c and height b

+ Area of rectangle with dimensions a and c.

$= 2 \times \frac{1}{2} ac + 2 \times \frac{1}{2} bc + ac \\ \\ = ac + bc + ac \\ \\ = 2ac + bc \\ \\ = 2(13)(3) + 7(3) \\ \\ = 78 + 21 \\ \\ = 99 \: sq \: cm$

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3 years ago

Read 2 more answers

Find 9P9 and 9C9. Why do the answers differ?

sveta [45]

We have been given two expressions $9P9\text{ and }9C9$ . We are asked to find the value of each.

To find 9P9, we will use permutations formula.

$^nP_r=\frac{n!}{(n-r)!}$ , where

P = Number of permutations,

n = The total number of objects in the set,

r = Number of objects being chosen from the set.

$9P9=\frac{9!}{(9-9)!}$

$9P9=\frac{9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{(0)!}$

$9P9=\frac{362880}{1}$ Using $0!=1$

$9P9=362880$

To find 9C9, we will use combinations formula.

$^nC_r=\frac{n!}{r!(n-r)!}$ , where

C = Number of combinations,

n = The total number of objects in the set,

r = Number of objects being chosen from the set.

$9C9=\frac{9!}{9!(9-9)!}$

$9C9=\frac{9!}{9!(0)!}$

$9C9=\frac{9!}{9!\cdot 1}$ Using $0!=1$

Cancelling out $9!$ , we will get:

$9C9=\frac{1}{1}$

$9C9=1$

The answers differ because order. With permutations we care about the order of the elements, while with combinations we don't.

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3 years ago

A researcher identifies a sample of teenagers and chooses two males, age 16

Alik [6]

I thinks it is matching pairs for random assignment on gender, age, & income status but I’m not sure

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3 years ago

Jessica Reads a story about a turtle that swam 16 feet in 24 seconds. She assumes that the time that it takes the turtle to swim

Zigmanuir [339]

Answer:

Time (secs) => distance (ft)

1 => ⅔

15 => 10

24 => 16

45 => 30

Step-by-step explanation:

Equation to represent this proportional relationship is $d = tk$ , where,

t = time

d = distance

k = constant of proportionality

To complete the table, let's find k given that the turtles swarm 16 ft (d) in 24 secs (t).

Substitute d = 16, t = 24 into the equation.

$d = tk$

$16 = 24k$

$\frac{16}{24} = k$ (division property of equality)

$\frac{2}{3} = k$

Let's complete the table by substituting the value of k and the other given value of t or d, as the case may be:

For 1 sec, let's find distance (d):

$d = tk$

$d = 1*\frac{2}{3}$

d = ⅔ ft

For 10 ft, let's find the time (t) taken:

$d = tk$

$10 = t*\frac{2}{3}$

Multiply both sides by 3

$10*3 = t*\frac{2}{3}*3$

$30 = t*2$

Divide both sides by 2

$\frac{30}{2} = \frac{t*2}{2}$

$15 = t$

t = 15 secs

For 45 secs, let's find distance (d):

$d = tk$

$d = 45*\frac{2}{3} = 15*2$

d = 30 ft

5 0

3 years ago