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3 years ago

8

1) After striking a pair of arcs from each endpoint of a line segment, what is the next step in constructing the segment's perpe

ndicular bisector?

2 answers:

qaws [65]3 years ago

6 0

After striking a pair of arcs from each endpoint of a line segment, just join the intersection point of the 1st pair (above the segment) with the intersection point
of the 2nd pair (under the segment)
And this is how you construct the segment's perpendicular bisector

oksian1 [2.3K]3 years ago

3 0

C) Use a straight edge to draw a vertical line between the points where each pair of arcs intersect.

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Unfortunately I can not answer this question because there are no underlined digits in your question

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3 years ago

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marysya [2.9K]

Answer:

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Step-by-step explanation:

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To make it into a percent, divide 100 by the denominator (20) and multiply it by the numerator (12)

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3 years ago

Mr. Hills horses, all together, eat 395 pounds of oats each month. If Mr. Hills has 5 horses, and each horse eats the sane amoun

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3 years ago

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vlada-n [284]

Answer:

-2

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3 0

3 years ago

Read 2 more answers

solve the given matrix equation for X. Simplify your answers as much as possible. (In the words of Albert Einstein, "Everything

vova2212 [387]

a.

$XA^{-1}=A^3$

$(XA^{-1})A=A^3A$

$X(A^{-1}A)=A^4$

$X=A^4$

b.

$AXB=(BA)^2$

$A^{-1}(AXB)B^{-1}=A^{-1}(BA)^2B^{-1}$

$(A^{-1}A)X(BB^{-1})=A^{-1}(BA)^2B^{-1}$

$X=A^{-1}(BA)^2B^{-1}$

c.

$(A^{-1}X)^{-1}=(AB^{-1})^{-1}(AB^2)$

$X^{-1}A=(BA^{-1})(AB^2)$

$X^{-1}A=B(A^{-1}A)B^2$

$X^{-1}A=B^3$

$(XX^{-1})A=XB^3$

$XB^3=A$

$X(B^3(B^3)^{-1})=A(B^3)^{-1}$

$X=A(B^3)^{-1}$

d. Not totally sure what the equation is supposed to be, but I guess it's

$ABXA^{-1}B^{-1}=A$

$ABX(BA)^{-1}=A$

$((AB)^{-1}(AB))X((BA)^{-1}(BA))=(AB)^{-1}A(BA)$

$X=(AB)^{-1}A(BA)$

$X=(B^{-1}A^{-1})A(BA)$

$X=B^{-1}(A^{-1}A)(BA)$

$X=(B^{-1}B)A$

$X=A$

7 0

3 years ago