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Readme [11.4K]
4 years ago
8

1) After striking a pair of arcs from each endpoint of a line segment, what is the next step in constructing the segment's perpe

ndicular bisector?
Mathematics
2 answers:
qaws [65]4 years ago
6 0
After striking a pair of arcs from each endpoint of a line segment, just join the intersection point of the 1st pair (above the segment) with the intersection point
of the 2nd pair (under the segment)
And this is how you construct the segment's perpendicular bisector


oksian1 [2.3K]4 years ago
3 0

C) Use a straight edge to draw a vertical line between the points where each pair of arcs intersect.

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harkovskaia [24]
Slope Is 0 so y=9


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What is the total surface area of the triangular prism? Select one:
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30 points is the answer
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Please help! Will mark as brainliest!
Juliette [100K]

Answer:

C

Step-by-step explanation:

Use elimination by multiplying thw whole top equation by 2. (both sides)

then cancel out y and solve for x. plug back in to get y

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3 years ago
Read 2 more answers
Draw a polygon with 4 right angles and 4 sides with the same length
alisha [4.7K]

Answer:

that would be a square, a square has 4 equivalent sides and angles

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
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