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Readme [11.4K]
3 years ago
8

1) After striking a pair of arcs from each endpoint of a line segment, what is the next step in constructing the segment's perpe

ndicular bisector?
Mathematics
2 answers:
qaws [65]3 years ago
6 0
After striking a pair of arcs from each endpoint of a line segment, just join the intersection point of the 1st pair (above the segment) with the intersection point
of the 2nd pair (under the segment)
And this is how you construct the segment's perpendicular bisector


oksian1 [2.3K]3 years ago
3 0

C) Use a straight edge to draw a vertical line between the points where each pair of arcs intersect.

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Find the second partial derivatives of the following functions
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(a) <em>z</em> = 3<em>x</em> ² - 4<em>xy</em> + 15<em>y</em> ²

has first-order partial derivatives

∂<em>z</em>/∂<em>x</em> = 6<em>x</em> - 4<em>y</em>

∂<em>z</em>/∂<em>y</em> = -4<em>x</em> + 30<em>y</em>

and thus second-order partial derivatives

∂²<em>z</em>/∂<em>x</em> ² = 6

∂²<em>z</em>/∂<em>x</em>∂<em>y</em> = -4

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∂²<em>z</em>/∂<em>y</em> ² = 30

where ∂²<em>z</em>/∂<em>x</em>∂<em>y</em> = ∂/∂<em>x</em> [∂<em>z</em>/∂<em>y</em>] and ∂²<em>z</em>/∂<em>y</em>∂<em>x</em> = ∂/∂<em>y</em> [∂<em>z</em>/∂<em>x</em>].

(b) <em>z</em> = 4<em>x</em> <em>eʸ</em>

∂<em>z</em>/∂<em>x</em> = 4<em>eʸ</em>

∂<em>z</em>/∂<em>y</em> = 4<em>x</em> <em>eʸ</em>

∂²<em>z</em>/∂<em>x</em> ² = 0

∂²<em>z</em>/∂<em>x</em>∂<em>y</em> = 4<em>eʸ</em>

∂²<em>z</em>/∂<em>y</em>∂<em>x</em> = 4<em>eʸ</em>

∂²<em>z</em>/∂<em>y</em> ² = 4<em>x</em> <em>eʸ</em>

<em />

(c) <em>z</em> = 6<em>x</em> ln(<em>y</em>)

∂<em>z</em>/∂<em>x</em> = 6 ln(<em>y</em>)

∂<em>z</em>/∂<em>y</em> = 6<em>x</em>/<em>y</em>

∂²<em>z</em>/∂<em>x</em> ² = 0

∂²<em>z</em>/∂<em>x</em>∂<em>y</em> = 6/<em>y</em>

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∂²<em>z</em>/∂<em>y</em> ² = -6<em>x</em>/<em>y</em> ²

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add simplify if possible I've already posted this once and I don't know what the answer was correct as somebody can do this I wi
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Answer: 15 + 53/77


Step-by-step explanation:


Multiplying a fraction by 1 does not change the value.

Any number divided by itself is 1.

For instance, 11/11 = 7/7 = 1.


12 + 1/7 + 3 + 6/11 = 15 + 1/7 + 6/11

= 15 + (11×1)/(11×7) + (7×6)/(7×11)

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It is faster to make sure to multiply by the "smallest" form of one that will work, but you don't have to. You only need to make sure that at the end there are no common factors in numerator and denominator, and that numerator is smaller than denominator.

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