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2 years ago

Draw a polygon with 4 right angles and 4 sides with the same length

2 answers:

6 0

Considering the characters you have stated I believe the figure is a square. Squares have 4 right angles and all the sides are the same length.

alisha [4.7K]2 years ago

4 0

Answer:

that would be a square, a square has 4 equivalent sides and angles

Step-by-step explanation:

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If an object is projected vertically upward from ground level with an initial velocity of 320 ft/sec, then its distance s above

PolarNik [594]

8<t<12 would be your answer buddy :)

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2 years ago

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How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y

son4ous [18]

Solution:

Given:

$x^2=6y$

Part A:

The vertex of an up-down facing parabola of the form;

$\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}$

Rewriting the equation given;

$\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\ \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\ \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\ \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\ \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}$

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

$\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}$

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

$\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}$

Therefore, the focus is;

$(0,\frac{3}{2})$

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

$\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}$

Therefore, the directrix is;

$y=-\frac{3}{2}$

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11 months ago

The dot plot below shows how many apple slices each girl at kaylas party ate which of the following represents the mean of the a

katovenus [111]

The answer to this question is 5.

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3 years ago

Kenyon earns $105 for mowing 3 lawns. How much<br>would Kenyon earn for mowing 10 lawns?

svp [43]

Answer:

$350

Step-by-step explanation:

3 lawns --------------> $105

find unit rate:

1 lawn -------------> $105 ÷ 3 = $35 per lawn

10 lawns --------> $35 per lawn x 10 lawns = $350

7 0

3 years ago

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Bruce Wayne trabaja en un proyecto inmobiliario, éste consiste en un edificio con forma de prisma de base triangular, cuya plant

Greeley [361]

Answer:

El área del gimnasio sería 2000 metros cuadrados

Step-by-step explanation:

Un lado del gimnasio será igual al lado de la cancha y el otro lado será igual al lado de la piscina.

Dado que tanto la cancha como la piscina tienen forma cuadrada. El lado de la cancha será raíz cuadrada de 2.500 m2 y el de la piscina será raíz cuadrada de 1.600 m2

Por lo tanto, el lado del gimnasio sería 50 y 40.

El área del gimnasio sería 50 * 40 = 2000 metros cuadrados

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2 years ago