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barxatty [35]
2 years ago
15

Draw a polygon with 4 right angles and 4 sides with the same length

Mathematics
2 answers:
mixas84 [53]2 years ago
6 0
Considering the characters you have stated I believe the figure is a square. Squares have 4 right angles and all the sides are the same length.
alisha [4.7K]2 years ago
4 0

Answer:

that would be a square, a square has 4 equivalent sides and angles

Step-by-step explanation:

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amid [387]

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I DONT KNOW BUT THAT'S MY ANSWER HOPE IT HELP

6 0
3 years ago
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Y=x^2-2x-1 and y=-3x+5 solved algebraically
eduard

Answer:

Step-by-step explanation:

y=x²-2x-1

and y=-3x+5

x²-2x-1=-3x+5

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=-3,2

when x=-3

y=-3×-3+5=9+5=14

when x=2

y=-3×2+5=-6+5=-1

so solutions are (-3,14) and (2,-1)

3 0
3 years ago
Plz help no guessing
Scorpion4ik [409]

The solution to a system of equations is the point that the 2 lines of the graph cross each other.

x = 1 and Y =4

Solution is (1,4)

Answer is C.

8 0
3 years ago
if a book is 33 hour and 45 min long ,how many days would it take you to read it if you read 6 hours a day ?
Lelu [443]

Answer:

6 days

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

5 0
3 years ago
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