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barxatty [35]
2 years ago
10

If x-2y=0 and 3x + y =7 what is the value of x

Mathematics
1 answer:
Agata [3.3K]2 years ago
6 0

Answer:

x=2

Step-by-step explanation:

If 3x + y = 7, then y= 7 - 3x.

Substitute in x - 2y = 0

So:

x - 2(7-3x)=0

x-14+6x=0

7x=14

x=2

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Step-by-step explanation:

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2 years ago
What are the solutions to the equation x2 + 4x – 12 = 0?
Alik [6]

Answer:

Step-by-step explanation:

X=2,-6

8 0
2 years ago
the mantle layer of earth begins about 70 kilometers underneath the surface. The layer called the outer core begins about 2970 k
gavmur [86]
Given:
<span>mantle layer of earth begins about 70 kilometers underneath the surface
</span><span>outer core begins about 2970 kilometers underneath the surface

Since we need to find the position of each layer </span><span>relative to the surface, the surface will serve as the point of origin or 0. Below the surface infers a negative value. So, Mantle layer is -70 km from the surface while outer core is -2970 km under the surface.

Comparing -70 and -2970, -70 has a greater value than -2970. The nearer the number is to the origin or 0, the higher its value.

Comparing the absolute greater value of -70 and -2970, -2970 has a greater absolute value. This is because absolute value is the positive value of the number. Absolute value of -70 is 70 while absolute value of -2970 is 2970. Thus, -2970 has a greater absolute value. </span>
6 0
3 years ago
HELP! Find v × w if v = 3i + 8j – 6k and w = –4i – 2j – 3k.
wolverine [178]

Using the determinant method, the cross product is

\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\3&8&-6\\-4&-2&-3\end{vmatrix}=\begin{vmatrix}8&-6\\-2&-3end{vmatrix}\,\vec\imath-\begin{vmatrix}3&-6\\-4&-3\end{vmatrix}\,\vec\jmath+\begin{vmatrix}3&8\\-4&-2\end{vmatrix}\,\vec k=-36\,\vec\imath+33\,\vec\jmath+26\,\vec k

so the answer is B.

Or you can apply the properties of the cross product. By distributivity, we have

(3i + 8j - 6k) x (-4i - 2j - 3k)

= -12(i x i) - 32(j x i) + 24(k x i) - 6(i x j) - 16(j x j) + 12(k x j) - 9(i x k) - 24(j x k) + 18(k x k)

Now recall that

  • (i x i) = (j x j) = (k x k) = 0 (the zero vector)
  • (i x j) = k
  • (j x k) = i
  • (k x i) = j
  • (a x b) = -(b x a) for any two vectors a and b

Putting these rules together, we get

(3i + 8j - 6k) x (-4i - 2j - 3k)

= -32(-k) + 24j - 6k + 12(-i) - 9(-j) - 24i

= (-12 - 24)i + (24 + 9)j + (32 - 6)k

= -36i + 33j + 26k

8 0
3 years ago
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H=2A/b1+b2. Hope this helps!!

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3 years ago
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