Answer:
B. 112°
Step-by-step explanation:
4x -4 = (3x+4) + (2x-44)
4x -4 = 5x - 40
5x - 4x = -4 + 40
x = 36
∠BCA = 3 * 36 + 4 = 112
let L = length and let W = width.
Use the equations 2L + 2W = 2750
and L = 5W + 15
Then do the steps as follows -
1. Plug the equation for what L equals into the first equation
2(5W+15) + 2W = 2750
2. Then distribute the 2
10W + 30 + 2W = 2750
3. Then add like terms
12W + 30 = 2750
4. Then subtract 30 from both sides
12W = 2720
5. Divide by 12 on both sides
W = 226.67
6. Then plug that into the second equation
L = 5(226.67) + 15
L = 1148.35 should be the answer
Just substitue
for
in the expression.



Answer:
16 ft²
Step-by-step explanation:
The complete question is attached.
A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.
The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.
Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:
The area of a trapezoid = [(3 + 5)/2] * 4
The area of a trapezoid = 16 ft²