Well I am going to assume you need slope-intercept form. So the equation is y=mx+b. m is slope, b is y intercept. So you just plug it in -6= -1/2(6)+b. -6=-3+b. Now you figure out for b so what does b have to be to make the equation equal. Well -3 so -6=-3+-3, or -6=-6.
y=-1/2x-3
Hope that helped
X2+7x-8=0
product=-8 times 1 = -8
sum= 7
{-1, 8}
x2-1x+8x-8=0
x(x-1)+8(x-1)=0
x+8=0 or X-1=0
x=-8
Answer:
0.530 (the 0 is not required)
Step-by-step explanation:
this is because another combination would be .35 which is less than .53 so this what i think the answer is.
--hope this helped :))
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3

Note: Negative time (-0.2) is not valid