The system of equations would be:
64x+132y = 1040
x = 2y
We multiply the number of adult tickets, 64, by the cost of the adult tickets, x. We multiply the number of student tickets, 132, by the cost of the student tickets, y. Together these add up to $1040.
We know that the cost of an adult ticket is twice as much as a student ticket, so x = 2y.
Answer:
Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable
Part 2) The number of minutes in a month must be equal to 50 minutes
Step-by-step explanation:
<u><em>The question is</em></u>
Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute
Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan
Part 1)
Let
x ---> the number of minutes
we have
<em>Cost Plan A</em>

<em>Cost Plan B</em>

we know that
In order for plan A to be cheaper than plan B, the following inequality must hold true.
cost of plan A < cost of plan B
substitute

solve for x
subtract 3x both sides

divide by 2 both sides

Rewrite

therefore
The number of minutes in a month must be greater than 50 in order for the plan A to be preferable
Part 2)
Let
x ---> the number of minutes
we have
<em>Cost Plan A</em>

<em>Cost Plan B</em>

we know that
In order for plan A cost the same than plan B, the following equation must hold true.
cost of plan A = cost of plan B
substitute

solve for x

therefore
The number of minutes in a month must be equal to 50 minutes
Answer:
77%
Step-by-step explanation:
Honestly I would just count it
the answer of division is 5.2
Answer:
Quadrants 3 and 4
Step-by-step explanation:
we have


using a graphing tool
The solution is the triangular shaded area between the three dashed lines
see the attached figure
The solution lies in Quadrants 3 and 4