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MAXImum [283]
3 years ago
11

The rhombus has vertices K(a, 0), M(a, b), and N(0, c). Which of the following could be coordinates of L?

Mathematics
2 answers:
Daniel [21]3 years ago
6 0

Answer with explanation:

The Vertices of Rhombus K L MN are ,  K(a, 0), M(a, b), and N(0, c).

Let Coordinates of Vertices of Point L ,which is one of the vertices among four vertices = (x,y)

As, Diagonals of rhombus bisect each other.

We will use the mid point formula ,to find the vertex of point L.

Mid Point Formula, of line joining two points , (p,q) and (r,s) is

       =(\frac{p+r}{2},\frac{q+s}{2})

Mid Point of ,K(a,0) and M (a,b) is

      =(\frac{a+a}{2},\frac{0+b}{2})\\\\=(\frac{2a}{2},\frac{b}{2})\\\\=(a,\frac{b}{2})

Mid Point of L (x,y) and N (0,c) is

    =(\frac{x+0}{2},\frac{y+c}{2})\\\\=(\frac{x}{2},\frac{y+c}{2})

As, Diagonal bisect each other,so

  a=\frac{x}{2}\\\\x=2 a\\\\ \frac{y+c}{2})=\frac{b}{2}\\\\y=b-c

Coordinates of vertices of L are =(2 a, b-c)

liq [111]3 years ago
5 0
The answer is (d,c)!!!
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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
The difference between half a number and 19
Alla [95]

Answer:

Step-by-step explanation:

9

7 0
3 years ago
Hi,so I've tried solving this problem for a while and I just don't get it,if you could give me some ideas I would appreciate it.
ziro4ka [17]

Answer:

187 cm²

Step-by-step explanation:

The bottom rectangle area is easy, it is 15*9 = 135 cm².

To find the area of the triangle, you only need the base width and its height (you don't need the hypotenuse). You can then use the formula: area triangle is base times half height.

The base width is 15-7 = 8 cm

The height is 22-9 = 13 cm

So the area of the triangle is 13*8/2 = 52 cm²

Together with the 135 of the rectangle that sums to 52+135 = 187 cm².

4 0
3 years ago
How can I solve this question???
eduard

Answer:

144°

Step-by-step explanation:

step 1

Find the measure of the central angle of the regular pentagon

Divide 360 degrees by 5 (the number of sides)

360\°/5=72\°

Let

c----> the center of the pentagon

we know that

m∠ECA=72°

m∠ACB=72°

therefore

m∠ECB=m∠ECA+m∠ACB

substitute the values

m∠ECB=72°+72°=144°

The measure of angle ECB is equal to the degrees that the pentagon rotate

5 0
3 years ago
If each quadrilateral below is a trapezoid blind the missing measure’s
uysha [10]

Answer:

measure of angle is E is 45 degrees besausw if you look closely then it is a

45,45,90, Triangle and so E is 45 degrees

measure of c = 360-45+79+134 = 102 ° degrees

8 0
2 years ago
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