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Inessa05 [86]
2 years ago
12

A mass on a spring bounces up and down in simple harmonic motion, modeled by the function s ( t ) = 3 sin t(t)=3 sin t where s i

s measured in centimeters and t t is measured in seconds. Find the rate at which the spring is oscillating at t = 9 t=9 s. Round your answer to four decimal places.
Mathematics
1 answer:
podryga [215]2 years ago
6 0

Answer:

Rate at which spring is oscillating 2.9631

Step-by-step explanation:

The governing equation for the position of the spring = 3 sin t

the change in position of the spring with respect to time is =\frac{ds}{dt}=3cost

given time t = 9 seconds,

To find the rate at which the spring is oscillating at the time, we insert the time 9 seconds into the the slot for t

\frac{ds}{dt}=3cos 9= 2.9631

rate at which it is oscillating = 2.9631

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Max lost 128 pounds in 16 weeks on his new weight-loss plan. What was his average change in weight per week?
Alex

Answer:

8 pounds per week

Step-by-step explanation:

AVG= total/time span

so

AVG= 128/16

AVG= 8 pounds per week

Hope this helps!

7 0
2 years ago
What is 2/9n-5=2+5/9n<br> Btw its solving equations with variables on both sides
vova2212 [387]

Answer:

n=-0.04761

Step-by-step explanation:

given 2\div 9n-5=2+5\div 9n

2\div 9n-5\div 9n=2+5

\frac{2-5}{9n}=7

-3=7\times 9n

63n=-3

n=\frac{-3}{63}=-0.04761

n=-0.04761 answer

4 0
3 years ago
-0.38 (8 repeating) written as a fraction is _____.
natulia [17]

Answer:

\frac{7}{18}

Step-by-step explanation:

We first let 0.38 (8 being repeated) be T.

Since z is recurring in 1 decimal places, we multiply it by 10. 10z = 3.88

Next, we subtract them. 10 r T 3.88 0.38 9x 3.5

Lastly, we divide both sides by 9 to get IC as a fraction. 3.5 T 9 35 90 7 18

7 0
3 years ago
Read 2 more answers
A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af
fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a  thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = T+(T_0-T)e^{-kt}

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110

So equation is

T(t) = 40+(30)e^{-0.8110t}\\

When t=1,

we get

T(1) = 40+(30)e^{-0.8110}\\\\=53.3324

5 0
2 years ago
Greatest common factor of five ​
arsen [322]

Answer:

GCF(greatest common factor) of 5 is 5.

6 0
3 years ago
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