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2 years ago

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A mass on a spring bounces up and down in simple harmonic motion, modeled by the function s ( t ) = 3 sin t(t)=3 sin t where s i

s measured in centimeters and t t is measured in seconds. Find the rate at which the spring is oscillating at t = 9 t=9 s. Round your answer to four decimal places.

1 answer:

podryga [215]2 years ago

6 0

Answer:

Rate at which spring is oscillating 2.9631

Step-by-step explanation:

The governing equation for the position of the spring = 3 sin t

the change in position of the spring with respect to time is = $\frac{ds}{dt}=3cost$

given time t = 9 seconds,

To find the rate at which the spring is oscillating at the time, we insert the time 9 seconds into the the slot for t

$\frac{ds}{dt}=3cos 9= 2.9631$

rate at which it is oscillating = 2.9631

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