5-10(|0.8-3/6|)
5-10(|1/5|)
5-(10)(0.2)
5-2
=3, so C would be your best answer.
Answer:
Honestly i think i know which diagrams your talking about but if it there is an option that has 20 squares and only 15 are shaded then thats the one u choose I'm thinking that option is c
I hope this helps please mark me brainliest
If it's three or more, the probability is 100%.
However, I will assume that you intend to draw only two balls and that you don't replace the first ball in the bag for the second draw.
So you draw one ball. The probability that it's red is 8/14 = 4/7.
You draw again. The probability of getting a second red is 7 (red balls remains) / 13 (balls remaining).
Assuming that the results of the first and second draws are independent,the probability of drawing two red balls is therefore (4/7)*(7/13) = 4/13.
Now, suppose instead of a red on the first draw you got white. The probability of this is 6/14 = 3/7.
Given the first ball is white, the probability of drawing a second white is 5/13.
So the probability of drawing two whites is (3/7)*(5/13) = 15/91.
The outcomes of drawing two reds or two whites are independent of each other, so you can add the probabilities to get the probability of drawing two balls of the same colour, i.e.
4/13 + 15/91 = 43/91
If you prefer to express it as a percentage, it's approximately 47.25%.
x > -1
-2x+5 < 7
-2x<2
Now since you divide by (-1) to get positive 2,you need to flip the sign
(-2)/(-1)= 2 2/(-1)=-2
SO
2x>-2
x > -1
To check the solution do not replace the x by -1 because it shouls be more than -1 (You can choose 0,1,2,3....)
Example choose x=3
-2x3+5<7
-6+5<7
-1<7
