What is the midpoint of the segment shown below?
1 answer:
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Answer:
3. 2
4. f(n) = 3 + 4(n - 1)
Step-by-step explanation:
3. The general term of the arithmetic sequence is given by:
A(n) = - 14 + (n - 1)(2)
To find the ninth term of this arithmetic sequence, just put in the general term.
∴ A(9) = - 14 + (9 - 1)(2) = - 14 + 8(2) = -14 + 16 = 2.
Therefore the ninth term in the arithmetic sequence is two.
4. To know which expression represents the given sequence, substitute different values for to conclude.
In Option A, f(n) = 4 + 3(n - 1). Substitute n = 1.
We get f(1) = 4 + 3(0) = 4. This is not the first term in the sequence and can be eliminated.
In Option B, f(n) = 4 + 3n. Substitute n = 1.
We get f(1) = 4 + 3(1) = 7, not 3 so can be eliminated.
Similarly in Option C, we get 7 and could be eliminated.
In Option D, f(n) = 3 + 4(n - 1). Substitute n = 1.
We get f(1) = 3 + 4(1 - 1) = 3, which is the first term in the sequence.
Similarly, f(2) = 3 + 4(2 - 1) = 3 + 4 = 7.
Substitute n = 3, 4 to get other terms as well.
So, we say f(n) = 3 + 4(n - 1) is the representation of the given arithmetic sequence.
Using the lognormal and the binomial distributions, it is found that:
- The 90th percentile of this distribution is of 136 dB.
- There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.
- There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.
In a <em>lognormal </em>distribution with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of
.
- The standard deviation is of
Question 1:
The 90th percentile is X when Z has a p-value of 0.9, hence <u>X when Z = 1.28.</u>
The 90th percentile of this distribution is of 136 dB.
Question 2:
The probability is the <u>p-value of Z when X = 150</u>, hence:
has a p-value of 0.9147.
There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.
Question 3:
10 signals, hence, the binomial distribution is used.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
For this problem, we have that , and we want to find P(X = 6), then:
There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.
You can learn more about the binomial distribution at brainly.com/question/24863377