Vertex form:
y-k=a(x-h)^2
h=-2,k=-20,y=-12 when x=0
thus;
-12+20=a(0+2)^2
8=4a
a=2
Equation:
y+20=2(x+2)^2
y+20=2(x^2+4x+4)
f(x)=2(x^2+4x+4)-20
f(x)=2x^2+8x+8-20
f(x)=2x^2+8x-20
Answer:SORRY:(
I do not really get the question so i do not know
Step-by-step explanation:
U should look these up on mathway
Shown below
<h2>
Explanation:</h2>
Here we have a line given by the equation:

This line is given in Slope-intercept form, recall that this form is as follows:

So in this case:

So a point that lies on the line is:

Another point would be:

So the line must pass through these two points. By using graphing tool we get the line shown below.
<h2>Learn more:</h2>
Matching graph with equations: brainly.com/question/13015874
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