Hi :)
20 mol NH3 x 6 H2O/4 NH3 = 30 mol H2O
Hope this helped :)
34.95 atm
lol i hope i’m not too late
The theoretical proportion is given by the balanced chemical equation:
2 mol NBr / 3 mol Na OH
Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3
Solve for x, x = 40 * 3/2 = 60 mol NaOH.
Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.
Answer: NBr3..
2.187 is the answer to this question
