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1 year ago

What should a simplified model of a large molecule like glucose show?

1 answer:

5 0

Glucose is the simplest sugar and carbohydrate that provides energy. The simplified model of glucose (C₆H₁₂O₆) shows carbon, hydrogen, and oxygen atoms linked together.

<h3>What is glucose?</h3>

Glucose is an example of a carbohydrate macromolecule that is further classified as a monosaccharide. They are crystalline and fundamental units of carbohydrates.

The molecular formula of glucose is C₆H₁₂O₆ and the mass is 180.156 g/mol. It is an aldohexose that contains an aldehydic functional group. In its structure, there are six oxygen atoms, six carbon atoms, and twelve hydrogen atoms.

Therefore, the glucose molecule is composed of C, H, and O.

Learn more about glucose here:

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Convert 23.064 mass to mg

Ierofanga [76]

ANSWER: 23064 mg

EXPLANATION: To convert grams to milligrams, we multiply by 1000.

23.064 g x 1000 = 23064 mg

3 0

3 years ago

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

Brut [27]

Answer: The smallest temperature change is shown by water.

Explanation:

To calculate the heat absorbed or released, we use the equation:

$q=mC\times \Delta T$ ......(1)

where,

q = heat absorbed = 200.0 J

m = mass of the substance

C = specific heat of substance

$\Delta T$ = change in temperature

As, the same amount of heat is getting absorbed in all the cases. So, the change in temperature will depend on the product of mass and specific heat.

For the given options:

Option a: 50.0 g Fe, $C_{Fe}=0.449J/g^oC$

We are given:

$m=50.0g\\C_{Fe}=0.449J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 0.449J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 0.449}=8.99^oC$

Change in temperature = 8.99°C

Option b: 50.0 g water, $C_{water}=4.18J/g^oC$

We are given:

$m=50.0g\\C_{water}=4.18J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 4.18J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 4.18}=0.96^oC$

Change in temperature = 0.96°C

Option b: 25.0 g Pb, $C_{Pb}=0.128J/g^oC$

We are given:

$m=50.0g\\C_{Pb}=0.128J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.128J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.128}=62.5^oC$

Change in temperature = 62.5°C

Option d: 25.0 g Ag, $C_{Ag}=0.235J/g^oC$

We are given:

$m=25.0g\\C_{Ag}=0.235J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.235J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.235}=34.04^oC$

Change in temperature = 34.04°C

Option e: 25.0 g granite, $C_{granite}=0.79J/g^oC$

We are given:

$m=25.0g\\C_{Fe}=0.79J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.79J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.79}=10.13^oC$

Change in temperature = 10.13°C

Hence, the smallest temperature change is shown by water.

5 0

3 years ago

Which of these processes are chemical reactions?

masya89 [10]

Rotting vegetables is a chemical change I think.

8 0

3 years ago

1. A 205 g sample of H20 at 25.0 °C is heated until the temperature reaches 75.0 °C. How many

Pachacha [2.7K]

Answer:

i really dont know

Explanation:

byeeeeeeeeeeeee

7 0

3 years ago

As a forensic expert, Jane needs to handle many biological evidence samples simultaneously. What is the basic precaution that sh

madreJ [45]

Answer:

B. use a new pair of gloves for each piece of evidence

Explanation:

When it comes to the basic precautions of handling biological evidence samples, one has to prevent cross contamination. This refers to the transfer of DNA from one evidence to another evidence; thus, it is important for Jane to use a new pair of gloves for each piece of evidence in order to prevent such occurrence.

Wearing of gloves will also prevent Jane's DNA from being implanted into the sample, and it will keep her safe from contracting blood-borne pathogens like those in the saliva, blood or semen.

7 0

3 years ago