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tino4ka555 [31]
1 year ago
7

Explain why beryllium looses electrons while ionic bonds,while Sulfur gains electrons.

Chemistry
1 answer:
balandron [24]1 year ago
3 0

Answer:

Since Beryllium has a larger atomic radius than Sulphur its electrons are not strongly attracted to the nucleus hence lost easily. But Sulphur has a small atomic radius hence electrons are more closely attracted to the nucleus.

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Draw a sketch of a cross section of a graduated cylinder illustrating the proper method for reading the volume
vekshin1

Answer:

in reading volume - you read from the bottom of the meniscus, which is the curve formed from the liquid in the graduated cylinder. Most graduated cylinders are in ml, so measure in the most accurate reading.

Explanation:

6 0
3 years ago
What strategies did you use when you played the balancing chemical equations game? Which atoms were the easiest to start examini
Yakvenalex [24]

<u>Answer:</u>

<em>Latest take an example to understand how </em><em>balancing of chemical reaction</em><em> is done that is assuming the reaction between iron as well as </em><em>oxygen which reacts to form rust.</em>

<u>Explanation:</u>

For this we would simply right the reactant and product that is expected. Then we would see the number of molecules of each element present on either side.

If in the reaction the element’s molecules are the same on both sides then the reaction would be correct and if not then we have to apply trial and error method to balance the equation such that the number of molecules of each element is equal on both sides of the reaction.

3 0
3 years ago
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PLEASE HELP! STAT! When aqueous solutions of cadmium chloride and sodium sulfide are mixed, a precipitate of cadmium sulfide for
Marina86 [1]

The equations are given down bellow in the picture.

8 0
3 years ago
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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.
Sindrei [870]

The molar solubility is 7.4×10^{-3} M and the solubility is  7.4×10^{-3} g/L .

Calculation ,

The dissociation of silver bromide is given as ,

AgBr → Ag ^{+} + Br^{-}

S  

 -          S        S        

Ksp =  [Ag ^{+} ] [ Br^{-} ]  =  [S] [ S ] = S^{2}

S = √ Ksp = √ 5. 5×10^{-5} = 7.4×10^{-3}

The solubility =7.4×10^{-3} g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of AgBr is dissociates and form one mole of each  Ag ^{+} and Br^{-} ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×10^{-3} mol/L = 7.4×10^{-3} M

To learn more about molar solubility ,

brainly.com/question/16243859

#SPJ4

7 0
1 year ago
Which of the following statements best describes why carbon can form a variety of organic compounds? Carbon atoms bond readily w
olga_2 [115]
Answer:
            <span>Carbon readily forms covalent bonds with other carbon atoms.

Explanation:
                   As we know approximately more than 95 % compounds, either isolated, discovered or synthesized belongs to organic compounds containing carbon atoms.
                  This great diversity of organic compounds is due to following facts.

1) Catenation:
                      Carbon has a peculiar behavior of self linkage. This self linkage of one carbon with another is called as catenation. In this way carbon can form a long chain of carbon atom. A branching can also take place when one carbon is bonded further to three of four carbon atoms.

2) Isomerism:
                     Secondly the carbon containing compounds show isomerism. In which molecular formula is same but structural formula is different. For example molecular formula C</span>₅H₁₂ can make following compounds,

                                a)  n-Pentane

                                b)  2-Methylbutane

                                c)  2,2-Dimethylpropane

3) Multiple Bonds:
                            Carbon can form multiple bonds i.e double bond like in alkenes and triple bonds like in alkyne. 

Due to these factors carbon gets very high number of opportunities to form large number of compounds.
7 0
3 years ago
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