1. 50% will be red
2. 100% will be roan
3. 50% roan and 50% white
Answer: a. True
Explanation:
Glomerular filtrate is formed by the difference in force of hydrostatic and osmotic pressure. This physical force involves:
Bowman's capsule hydrostatic pressure: This includes the pressure that develops in the Bowman's capsule against the fluid to be filtrated expelled out by the glomerulus.
Glomerular hydrostatic pressure: The glomerulus is the main site of production of filtrate. It is higher than the average blood capillary hydrostatic pressure. It allows the water and solute molecules to be filtrated out of the plasma membrane.
Colloid osmotic pressure: The osmotic pressure which is generated by the large molecules is the colloid osmotic pressure. It is created by the plasma proteins. This pressure draws water from the glomerulus.
Answer:
Explanation:
Parasympathetic Nervous System. The parasympathetic nervous system is an anatomically defined division of the autonomic nervous system, being that part whose motor components run in cranial nerves III, VII, IX, and X and in the sacral nerves.
Answer:
D. The tubes allow water and nutrients to be transported throughout
the plant.
Explanation:
option D supports the description of the cells. The long , vertical tubes transport water and nutrients and are most likely xylem and phloem vessels.
option A is wrong since, chloroplasts inside the cell helps in absorbing sunlight.
option C is also wrong, because water loss is controlled by the stomata in the leaves and they are not long tubes.
option B could possibly be right but option D is better suited.
Answer:
This question lacks options, the options are:
A) FF and ff
B) FF and Ff
C) Ff and Ff
D) Ff and ff
The answer is D (Ff and ff for parent 1 and 2 respectively)
Explanation:
This question depicts a single gene coding for fur colour in mice. The gene controls two traits, black fur and white fur, encoded by alleles F and f respectively.
According to the question, a pair of mice has been bred several times to generate the same data of 22 black fur and 23 white fur mice. Based on this data, it shows that the phenotypic ratio of black to white mice is 1:1.
To get a 1:1 phenotypic ratio of black fur offspring to white fur offspring, the parents mice must have genotypes Ff (heterozygous) and ff (same recessive alleles).
In a cross between parents Ff × ff (see punnet square), offsprings with the following genotypes will be produced: Ff, Ff, ff and ff. Ff is black furred while ff is white furred.
Ff (2) : ff (2) is equivalent to Ff (1) : ff (1).
Hence, a data of 22 black mice and 23 white mice which represents a 1:1 ratio will only be produced by parents mice with genotypes: Ff and ff.
