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asambeis [7]
3 years ago
11

Three physical forces are involved in glomerular filtration: glomerular capillary blood pressure, plasma-colloid osmotic pressur

e, and Bowman's capsule hydrostatic pressure.
a. True
b. False
Biology
1 answer:
Elodia [21]3 years ago
7 0

Answer: a. True

Explanation:

Glomerular filtrate is formed by the difference in force of hydrostatic and osmotic pressure. This physical force involves:

Bowman's capsule hydrostatic pressure: This includes the pressure that develops in the Bowman's capsule against the fluid to be filtrated expelled out by the glomerulus.

Glomerular hydrostatic pressure: The glomerulus is the main site of production of filtrate. It is higher than the average blood capillary hydrostatic pressure. It allows the water and solute molecules to be filtrated out of the plasma membrane.

Colloid osmotic pressure: The osmotic pressure which is generated by the large molecules is the colloid osmotic pressure. It is created by the plasma proteins. This pressure draws water from the glomerulus.

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The organ is the LUNGS.
The lungs excrete carbon dioxide and water vapour through metabolism. 
The lungs are used for breathing in humans, through the lungs we take in oxygen which is carried by the blood to all the part of the body and we exhale carbon dioxide which is a waste product generated as a result of the reactions that occur in the body. 
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3 years ago
Need Help!!! 30 points! You are monitoring coral growth on a specific site for several months. Over time, you notice that some o
creativ13 [48]

Answer:

A

Explanation:

The coral reef is experiencing succession, so over time the coral will continue to die off gradually as the zooxanthellae algae leaves the coral polyps.

3 0
3 years ago
3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
konstantin123 [22]

Answer and Explanation:

Available Data:

  • 1 gr beets = 2,000 cal
  • NPP = GPP – Respiration = 120 grams/m2/day
  • NPP= Net primary productivity of a system
  • GPP= Gross productivity of the producers
  • Respiration loss 25% of NPP
  • Insolation energy is 800 calories/cm2/day
  • % Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

8 0
3 years ago
Why do you suppose the united states still uses the english system for everyday measurements while almost every other country us
Alchen [17]
Answer:
Because the English measurement system has been in use for a very long time, it will be costly and time consuming to change from the English to SI units. Many technological measurements, products, and tools were developed in English units.

The cost of converting all measurements to SI units will be costly and will require a long period of time. Conversions between the English and the SI system of units appear to be more cost-effective than hardware changes.

Example:
It will be costly to convert designs for bridges, tunnels, locomotives, automobiles, and other hardware to the SI system. Although new designs are being performed in SI units, much useful hardware based on English units still remain.

Eventually, it is likely that complete conversion from English to SI units will happen, albeit slowly.
6 0
3 years ago
Why can plant cells photosynthesiz, but animal cells cannot?
nignag [31]

Answer:

c is the answer

Explanation:

most likely c

4 0
2 years ago
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