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Anna71 [15]
3 years ago
13

Jam is made from 4 parts fruit and 3 parts sugar. How much sugar is needed to make jam from 1.5kg of fruit.. show workings

Mathematics
2 answers:
marta [7]3 years ago
8 0
Well to solve this we need to dilute the sugar measurement sence the fruit count is lower, so first find the dilution amount in the fruit
4/1.5= 2.6
so to find the sugar you divide 3 by 2.6
3/2.6= 1.1

So you would need 1.1kg of sugar to make the jam!

Hope this helped!!
Pani-rosa [81]3 years ago
6 0

Answer:

1.1kg of sugar

Step-by-step explanation:

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Alika [10]

Given:

The expression is 5+4\times 2+6-2\times 2-1.

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

5+4\times 2+6-2\times 2-1

Now,

(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1

(5+4)\times 2+6-2\times 2-1=18+6-5

(5+4)\times 2+6-2\times 2-1=18+1

(5+4)\times 2+6-2\times 2-1=19

There are more ways to apply the parenthesis, but we do not get 19.

5+4*\left(2+6\right)-2*2-1=32\neq 19

5+4*2+\left(6-2\right)*2-1=20\neq 19

5+4*2+6-2*\left(2-1\right)=17\neq 19

And many more possibilities.

Therefore, the expression after inserting the parentheses is (5+4)\times 2+6-2\times 2-1.

6 0
3 years ago
Consider the line y=9x-1.
OLEGan [10]

Step-by-step explanation:

Slope=9

i)

y−y1=m(x−x1)

When line is parallel

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<h3>59 = 9x-y </h3>

When line is perpendicular

y+5=-1/9(x-6)

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9y + 45 = -x+6

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5 0
2 years ago
Find x and explain please
pav-90 [236]

Answer:


Step-by-step explanation:

1) isosceles= two sides are congruent

2) 9x-13=4x+2

-4x

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7 0
3 years ago
Write expression using the distributive property to find the product of 9 x82
irga5000 [103]

Answer:

Step-by-step explanation:

9 * 82 = ( 10-1) * 82

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5 0
3 years ago
Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
Free_Kalibri [48]

Answer:

1/3

Step-by-step explanation:

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

Each side of Polygon FFF was multiplied by a certain value, known as the scale factor , to result in an area that is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

[Show me an example of how scale factor affects area]

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction

 

 

\begin{aligned} A &= \left(l\times\dfrac1{10}\right)\times\left(w\times\dfrac1{10}\right) \\ \\ A&= l\times w\times\dfrac1{10}\times\dfrac1{10} \\ \\ A&= lw \times \left(\dfrac1{10}\right)^2\end{aligned}  

 

 

 

 

 

 

 

 

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction\left(\dfrac1{10}\right)^2  

 

left parenthesis, start fraction, 1, divided by, 10, end fraction, right parenthesis, start superscript, 2, end superscript

Hint #22 / 3

The area of a polygon created with a scale factor of \dfrac1x  

x

1

​  start fraction, 1, divided by, x, end fraction has \left(\dfrac1{x}\right)^2(  

x

1

​  )  

2

left parenthesis, start fraction, 1, divided by, x, end fraction, right parenthesis, start superscript, 2, end superscript the area of the original polygon:

\left(\text{scale factor}\right)^2=\text{fraction of the area the scale copy has}(scale factor)  

2

=fraction of the area the scale copy hasleft parenthesis, s, c, a, l, e, space, f, a, c, t, o, r, right parenthesis, start superscript, 2, end superscript, equals, f, r, a, c, t, i, o, n, space, o, f, space, t, h, e, space, a, r, e, a, space, t, h, e, space, s, c, a, l, e, space, c, o, p, y, space, h, a, s

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF. Let's substitute \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction into the equation to find the scale factor.

\left(\dfrac1{?}\right)^2=\dfrac19(  

?

1

​  )  

2

=  

9

1

​  left parenthesis, start fraction, 1, divided by, question mark, end fraction, right parenthesis, start superscript, 2, end superscript, equals, start fraction, 1, divided by, 9, end fraction

The scale factor is \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction.

Hint #33 / 3

Aimar used a scale factor of \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction to go from Polygon FFF to Polygon GGG.

4 0
3 years ago
Read 2 more answers
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