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lina2011 [118]
3 years ago
14

To complete this component you will need to insert parentheses in Expression 2 to change the order of operations so the expressi

on will have a value of 19. 5+4*2+6-2*2-1
Mathematics
1 answer:
Alika [10]3 years ago
6 0

Given:

The expression is 5+4\times 2+6-2\times 2-1.

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

5+4\times 2+6-2\times 2-1

Now,

(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1

(5+4)\times 2+6-2\times 2-1=18+6-5

(5+4)\times 2+6-2\times 2-1=18+1

(5+4)\times 2+6-2\times 2-1=19

There are more ways to apply the parenthesis, but we do not get 19.

5+4*\left(2+6\right)-2*2-1=32\neq 19

5+4*2+\left(6-2\right)*2-1=20\neq 19

5+4*2+6-2*\left(2-1\right)=17\neq 19

And many more possibilities.

Therefore, the expression after inserting the parentheses is (5+4)\times 2+6-2\times 2-1.

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A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.

3x-y=0 → 2(3x-y=0) = 6x - 2y = 0

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The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22


B. So now we combine them:

6x - 2y = 0

+ + +

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= = =

11x + 0 = 22 ← The answer


C. Now that we have the equation 11x = 22, we solve for x

11x = 22 ← Divide both sides by 11

x = 2 ← The answer


D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:

5(2)+2y = 22

10 + 2y = 22

2y = 12

y = 6


<u>Therefore, the solution to this problem is x = 2 and y = 6</u>


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