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Leni [432]
3 years ago
15

Evaluate v(x) = 14-3x when x=-3, 0 and 4.

Mathematics
2 answers:
PtichkaEL [24]3 years ago
5 0

Answer:

v(-3)=23\\v(0)=14\\v(4)=2

Step-by-step explanation:

v(x)=14-3x

v(-3)=14-3(-3)\\\\v(-3)=14-(-9)\\\\v(-3)=23

v(0)=14-3(0)\\\\v(0)=14-0\\\\v(0)=14

v(4)=14-3(4)\\\\v(4)=14-12\\\\v(4)=2

Fofino [41]3 years ago
3 0

Answer:

2 = v(4) \\ 14 = v(0) \\ 23 = v(-3)

Step-by-step explanation:

14 - 3(4) = 14 - 12 = 2 \\ 14 - 3(0) = 14 ± 0 = 14 \\ 14 - 3( -3) = 14 + 9 = 23

Double negatives are ALWAYS positive, so be EXTREMELY careful on the first exercise.

I am joyous to assist you anytime.

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Brian, Kelsey, and Geoff each have a remote-controlled car. They simultaneously started their cars and drove them in a straight
jasenka [17]

Answer:

The correct option is 1.

Step-by-step explanation:

It is given that the Brian, Kelsey, and Geoff each have a remote-controlled car. They simultaneously started their cars and drove them in a straight line away from a motion sensor.

It means they are travelling at a constant rate.

Slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

From the given table it is clear that the of Brian's car from the sensor is 34 at 1 sec and 38 at 3 sec. The rate of change is

m=\frac{38-34}{3-1}=2

It means the Brian's car traveled at the rate of 2 cm per sec.

From the given table it is clear that the of Brian's car from the sensor is 27 at 1 sec and 31 at 3 sec. The rate of change is

m=\frac{31-27}{3-1}=2

It means the Kelsey's car traveled at the rate of 2 cm per sec.

From the given table it is clear that the of Brian's car from the sensor is 27 at 1 sec and 33 at 3 sec. The rate of change is

m=\frac{33-27}{3-1}=3

It means the Geoff's car traveled at the rate of 3 cm per sec.

Since Brian's and Geoff's car traveled at the same rate, therefore option 1 is correct.

7 0
3 years ago
Read 2 more answers
What’s the distance from c to d ?
Anon25 [30]
It’s 5 since you’d use Pythagorean theorem
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valentina_108 [34]

Answer:

ok ok ok chill out

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Step-by-step explanation:

3 0
3 years ago
The difference of two numbers is 90 and their quotient is 10
bija089 [108]
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90

2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10


Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b

2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10

3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100

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Answer: The numbers are 100 and 10</span>
3 0
4 years ago
A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is ce
lubasha [3.4K]
<h2>Answer:</h2>

\boxed{(5(-\sqrt{2}+\sqrt{6}),5(\sqrt{2}+\sqrt{6}))}

<h2>Step-by-step explanation:</h2>

The origin of the coordinate system is the center of the circle. So we have an angle that measures 5\pi/12=75^{\circ}. so the x-coordinate and y-coordinate can be found, by using trigonometry as follows:

x=20cos(5\pi/12)=5\sqrt{6}-5\sqrt{2} \\ \\ Arranging:\\ \\x=5(-\sqrt{2}+\sqrt{6}) \\ \\y=20sin(5\pi/12)=5\sqrt(6)+5\sqrt{2} \\ \\ Arranging:\\ \\y=5(\sqrt{2}+\sqrt{6})

Finally, the exact value of the position of the rider after the carousel rotates 5\pi/12 radians is:

\boxed{(5(-\sqrt{2}+\sqrt{6}),5(\sqrt{2}+\sqrt{6}))}

3 0
3 years ago
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